Answer:
The Magnifying power of a telescope is 
Explanation:
Radius of curvature R = 5.9 m = 590 cm
focal length of objective 
= 
⇒ = 
⇒ = 295 cm
Focal length of eyepiece 
= 2.7 cm
Magnifying power of a telescope is given by,
therefore the Magnifying power of a telescope is
The formula for both is v(t) = v0 + a*t
b) v(8) = 0 + 6m/s^2 *8s = 48 m/s
now we know the beginning (2) and end speed (14), but not the time:
c) 14 = 2 + 1.5*t => t = (14-2)/1.5 = 8 seconds
Answer:
1 ohm
Explanation:
since there are two identical resistors, one resistor will be
R = 
=2ohm [ proven as in series 
]
to calculate the equivalent resistance when in parallel:
so,
While the answer is that it does, it transmits light VERY poorly. Most of the light bounces off it and the rest is refracted into the ocean. This is why you can't see much that is far away from you in the ocean unlike if you're just on land.
Neutral. A neutron doesn’t have a positive charge like a proton or a negative charge like an electron.
