Answer:8.75 s,
136.89 m
Explanation:
Given
Initial velocity
velocity after 5 s is 
Therefore acceleration during these 5 s


therefore time required to stop
v=u+at
here v=final velocity =0 m/s
initial velocity =31.29 m/s


(b)total distance traveled before stoppage


s=136.89 m
Answer:
d. velocity slows down and angle changes
Explanation:
The correct answer is A, 2x^3 - x^2 +3x +7
Explanation:
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