Answer:
1. 5 m/s
2. 8 m/s
3. 10 s
4. 3 m/s
Explanation:
1. Average speed = distance / time
s = 20 m / 4 s
s = 5 m/s
2. First, find the time to travel from A to B:
60 m = 10 m/s × t
t = 6 s
Now find the average speed from A to C:
s = 80 m / (6 s + 4 s)
s = 8 m/s
3. If t is the time traveling from C back to B, and the average speed of the whole trip is 5 m/s, then:
5 m/s = 100 m / (6 s + 4 s + t)
t = 10 s
4. Average velocity = displacement / time
v = 60 m / 20 s
v = 3 m/s
The answer would be the one where the left side is less than or equal to 130 because 130 has to be the greatest value and the value of the w's cannot exceed 130, but they can equal it
Answer:
a) always. b) electric field lines are defined by the path positive test charges travel.
Explanation:
By convention, field lines always follow the direction that it would take a positive test charge (small enough so it can´t disrupt the field created by a charge distribution), under the influence of an electric field, at the same point where the test charge is located.
So any positive charge, subject to an electric field influence, moves along the field line that passes through its current position, in the same way that a positive test charge would.
We could say also that the electric force on a positively charged particle is in the same direction as the electric field that produces that force (due to some charge distribution) , which is true, but it doesn´t explain why.
Answer:
(a). 12 plants
(b). 3171 $
Explanation:
(a)first convert units of 100 billion kWh/year into Watts(W)
also convert the units of 1000 MW into Watts(W)
1 billion = 10^9
1 year = 365*24 = 8760 hrs
so
100 billion kWh/year = 1
= 
W
1000 MW = 
no. of plants = 
= 11.4
So 12 plants required
(b)
savings = unit price*total units
= 
= 3170.9 =3171 $
