2. This diagram represents a top-down view of an experiment on a table. The 250 g and 100 g masses are falling and are pulling t
he block. Draw an arrow to show which way the block will move. You do not have to interpret the size of the arrow, just draw the direction.
2 answers:
Answer:
According to the data given in the question, experiment on table two pulling and falling masses are arranged in the fig. 250 g is pulling right side and 100 g pulling down. The gravitational force is common to both the masses, so we cannot say that the block moves towards heavier mass, also the block does not move towards the lighter mass.
Obviously, the effect of heavier mass of 250 g is more on the block, so the block moves towards right bottom corner. i.e., diagonally between two masses
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I believe this is what you have to do:
The force between a mass M and a point mass m is represented by
So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁
So F₁ = G(Mm/r^2)
Now the distance has doubled so lets account for this in F₂:
F₂ = G(Mm/(2r)^2)
Now square the 2 that gives you four and we can pull that out in front to give
F₂ = G(Mm/r^2)
Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations
now we see that:
F₂ = F₁
So the second force will be 0.25 (1/4) x 1600 or 400 N.
Answer:
The magnitude of the electric flux is
Explanation:
Given that,
Electric field = 2.35 V/m
Angle = 25.0°
Area
We need to calculate the flux
Using formula of the magnetic flux
Where,
A = area
E = electric field
Put the value into the formula
Hence, The magnitude of the electric flux is