Centripetal acceleration is the motion inwards towards the center of a circle. It is given by the square of velocity, divided by the radius of the circular path.
ac = v²/r, where ac is the centripetal acceleration in m/s²
Therefore,
Centripetal acceleration = 3²/20m
= 9/20m
= 0.45 m/s²
Thus, the centripetal acceleration is 0.45 m/s²
Answer:
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
Explanation:
This is an exercise of average speed, which is defined with the variation of the distance in the unit of time
v = (y₃ - y₂) / (t₃-t₂)
the midpoint of a magnitude is the sum of the magnitude between 2
t_mid = (t₂ + t₃) / 2
the same reasoning is used for the mean acceleration
a = (v_f - v₀) / (t_f - t₀)
in our case
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
Answer:
the ball experiences the greater momentum change
Explanation:
You have to take into account that momentum change is given by
where vf and vb are the speed of the object after and before the impact.
In the case of the ball you have
where the minus of vf is included due to the motion is in an opposite direction regarding with vb
And for the lump
Hence, the ball experiences the greater change
hope this helps!!
Answer:
a. True
Explanation:
It's commonly used in the bain bridge diagram determining positive rays