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Rasek [7]
3 years ago
8

An object in free fall is at heights y1, y2, and y3 at times t1, t2, and t3 respectively.

Physics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

  a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)

Explanation:

This is an exercise of average speed, which is defined with the variation of the distance in the unit of time

         v = (y₃ - y₂) / (t₃-t₂)

the midpoint of a magnitude is the sum of the magnitude between 2

         t_mid = (t₂ + t₃) / 2

the same reasoning is used for the mean acceleration

         a = (v_f - v₀) / (t_f - t₀)

   

in our case

        a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)

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