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3 years ago

Thoughts on the sat for those who have taken it?

Mathematics

2 answers:

melamori03 [73]3 years ago

7 0

In my opinion it's very challenging, but if you study you'll be okay.

Vladimir [108]3 years ago

4 0

Well its hard, they do weigh the reading part alot. They have practice SATs online on Cracksat.net. Really helpful. Study alot

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FIND.......16 2/3 % of 96 lamps

r-ruslan [8.4K]

Convert percentage to fraction by dividing by 100
16 2/3 = 16 2/3 ÷ 100 = 1/6

16 2/3 % of 96 = 1/6 x 96 = 16

Ans: 16 2/3 % of 96 lamps = 16

4 0

3 years ago

2. If y varies inversely as x and y = 3 when x = 5, find x when y = 2.5

4vir4ik [10]

Answer:

Step-by-step explanation:

From the law of variation,

y <> 1/x, where <> is the constant of proportionality. Therefore

y = k/x where k is a constant

3 = k/5 and k = 15

To find x when y = 2.5(5/2)

Go back to the second equation

y = k/x

5/2 = 15/x

When you cross multiply

5x = 30.

Divide through by 5,

x = 6.

8 0

3 years ago

PLEASE PLEASE PLEASE HELP

aksik [14]

Answer: X- 0,1,2,3,4 and Y-0,6,12,18,24

Step-by-step explanation: i had to take this test ): luck

5 0

3 years ago

Find (f*g) (x) for the following functions. f(x) = 9x2 – 2x – 9 g(x) = 11x – 9

e-lub [12.9K]

Answer:

all work is shown and pictured

4 0

3 years ago

Read 2 more answers

Two number cubes are rolled for two separate events:

andrew11 [14]

Answer: $\bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}$

Step-by-step explanation:

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

$P(B|A)=\dfrac{P(B\cap A)}{P(A)}$

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

(2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

(3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

(4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

(5, 4), (5, 3), (5, 2), (5, 1)

(6, 3), (6, 2), (6, 1)

= 30

P(B) = (1, 2), (2, 1) sum = 3

(1, 5), (2, 4), (3, 3), (4, 2), (5, 1) sum = 6

(3, 6), (4, 5), (5, 4), (5, 4), (6, 3) sum = 9

(6, 6) sum = 12

= 12

P(A ∩ B) = (1, 2), (2, 1)

(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

(3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

= 11

7 0

3 years ago