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nataly862011 [7]
3 years ago
12

Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia

l as high as 500 km (or even higher) above the surface. Io has a mass of 8.93×1022 kg and a radius of 1821 km . For this calculation, ignore any variation in gravity over the 500-km range of the debris.A. How high would this material go on earth if it were ejected with the same speed as on Io?
Physics
1 answer:
Anton [14]3 years ago
8 0

Answer:

91.64 km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

Explanation:

According to Newton Law of gravitation:

g=\frac{Gm}{r^2}

Where:

G is gravitational constant=6.67*10^{-11} m^3/kg.s^2

For Moon lo g is:

g_M=\frac{6.67*10^{-11}*8.93*10^{22}}{(1821*10^3)^2m^2} \\g_M=1.7962 m/s^2

According to law of conservation of energy

Initial Energy=Final Energy

K.E_i+mgh_i=K.E_f+mgh_f

\frac{1}{2}m(v_0)^2+mgh_o= \frac{1}{2}m(v_f)^2+mgh_f\\At\ maximum\ height\ v_f=0\\\frac{1}{2}m(v_0)^2+0=mgh_f\\v_0=\sqrt{2gh_f}

For Jupiter's moon Io:

Velocity is given by:

v_0_M=\sqrt{2g_Mh_f_M}

For Earth Velocity is given by:

v_0_E=\sqrt{2g_Eh_f_E}

Now:

v_o_M=v_o_E

\sqrt{2g_Mh_f_M}=\sqrt{2g_Eh_f_E}\\h_f_E=\frac{g_Mh_f_M}{g_E}

g_E=9.8 m/s^2

g_m=1.7962 m/s^2, As\ Calculated\ above

h_f_E=\frac{1.7962*500*10^3m}{9.8} \\h_f_E=91642.85 m\\h_f_E=91.64Km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

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Answer:

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Explanation:

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Substituting:

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The zones of falling air are those between 20 and 30 latitudes on the western borders of continents (high pressure and dry weather). As a result, the moisture continues to decrease as the air is compressed and warmed as it falls.

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