Answer:
a)mass = 300kg
b) no of atoms = 1.81 x 10^26atoms.
c)Fission Activity = 207Bq
d) no of fissions = 1.79 × 107 d^-1
Explanation:
a)mass= (3×10-4)(10^6kg) = 300kg
b) no of atoms = (300kg) X (6.022×10^23/kg) = 1.81 x 10^26atoms.
c)Fission Activity = (0.69)(300kg) = 207Bq
d) no of fissions = (207)(86400) = 1.79 × 107 d^-1
∆g for these initial partial pressures is 10,403.31 KJ.
ΔG gets increasingly positive as a product gas's partial pressure is raised. ΔG becomes more negative as the partial pressure of a reactant gas increases.
∆g = RT ln (q/k)
In this equation: R = 8.314 J mol⁻¹ K⁻¹ or 0.008314 kJ mol⁻¹ K⁻¹
K = 325
If ΔG < 0, then K > Q, and the reaction must proceed to the right to reach equilibrium.
∴∆g = RT ln (q/k)
= 8.314 × 298 ln ( 5 / 325)
= 2477.57 ln 0.015
= 2477.57 × (-4.199)
= 10,403.31 KJ
Products are preferred over reactants at equilibrium if G° 0 and both the products and reactants are in their standard states. When reactants are preferred above products in equilibrium, however, if G° > 0, K 1. At equilibrium, neither reactants nor products are preferred if G° = 0, hence K = 1.
Therefore, ∆g for these initial partial pressures is 10,403.31 KJ.
Learn more about equilibrium here:
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Explanation:
If the size and direction of the forces on the object are exactly balanced , then there is no net force acting on the object
Answer:
a current will be induced.
Explanation:
That information describes the plane's speed.
If he had also told them what direction they were flying, then
they would have been able to put the two pieces of information
together, and they would know the plane's velocity.