The Basketball with the greatest gravitational potential energy is : Basketball 4 feet above the ground ( c )
<u>Given data :</u>
masses = constant
H₁ = 2 ft
H₂ = 3 ft
H₃ = 4 ft
g = 9.81 m/s²
<h3><u>Procedure to determine the basketball with the greatest gravitational P.E </u></h3>
we will apply the equation below
Gravitational potential energy ( U ) = mgh
U = 2 * 9.81 = 19.62
U = 3 * 9.81 = 29.43
U = 4 * 9.81 = 39.24
From the calculations the basketball with the greatest gravitational potential energy is the basketball at 4ft above the ground
Learn more about gravitational potential energy : brainly.com/question/15896499
GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N
<span>GPE=mgh=675(26000)=17.55x10^6J</span>
B
A quantity which does not depend on direction is called a scalar quantity. Vector quantities have two characteristics, a magnitude and a direction. Scalar quantities have only a magnitude. ... The resulting motion of the aircraft in terms of displacement, velocity, and acceleration are also vector quantities.
Here, we are required to determine which combination of molecules will produce ammonia with no leftovers.
Option A: 2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.
First, it is important to know that both Nitrogen and Hydrogen used in the production of ammonia are diatomic.
Secondly, Nitrogen and Hydrogen are in the ratio 1 : 3.....
As such, the coefficient of hydrogen should be thrice that of Nitrogen to ensure that there are no leftovers.
Therefore, option A which has:
2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.
Read more:
brainly.com/question/24396848
Answer:
6000 J
Explanation:
Potential energy = mass*gravity*height (U = m*g*h)
In this case g = 10 so
U = 75*10*8 = 6000 J (joules) [kg * m^2/s^2]