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3 years ago

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:

Physics

1 answer:

fgiga [73]3 years ago

8 0

Here, we are required to determine which combination of molecules will produce ammonia with no leftovers.

Option A: 2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.

First, it is important to know that both Nitrogen and Hydrogen used in the production of ammonia are diatomic.

Secondly, Nitrogen and Hydrogen are in the ratio 1 : 3.....

As such, the coefficient of hydrogen should be thrice that of Nitrogen to ensure that there are no leftovers.

Therefore, option A which has:

2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.

Read more:

brainly.com/question/24396848

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Which of the following statements is true? Communicable diseases cannot be transmitted by nonliving objects. Sexually transmitte

Lemur [1.5K]

Answer:

Sexually transmitted diseases are spread by direct contact with bodily fluids.

Explanation:

if you have a disease you can give it to someone by having sex because your fluids go into or either combine

4 0

3 years ago

Read 2 more answers

A particle has ~r(0) = (4 m) ˆ and ~v(0) = (2 m/s)ˆı. If its acceleration is constant and given by ~a = −(2 m/s 2 ) (ˆı +ˆ), a

Troyanec [42]

The particle has $\vec r(0)=(4\,\mathrm m)\,\vec\imath$ and $\vec v(0)=\left(2\frac{\rm m}{\rm s}\right)\,\vec\imath$ , and is undergoing a constant acceleration of $\vec a=-\left(2\frac{\rm m}{\mathrm s^2}\right)(\vec\imath+\vec\jmath)$ .

This means its position at time $t$ is given by the vector function,

$\vec r(t)=\vec r(0)+\vec v(0)t+\dfrac12\vec a t^2$

$\implies\vec r(t)=\left[4\,\mathrm m+\left(2\dfrac{\rm m}{\rm s}\right)t-\left(1\dfrac{\rm m}{\mathrm s^2}\right)t^2\right]\,\vec\imath-\left(1\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath$

The particle crosses the x-axis when the $\vec\imath$ component is 0 for some time $t>0$ , so we solve:

$4+2t-t^2=0\implies t^2-2t+1=5$

$\implies(t-1)^2=5$

$\implies t-1=\pm\sqrt5$

$\implies t=1\pm\sqrt5$

The negative square root introduces a negative solution that we throw out, leaving us with $\boxed{t=1+\sqrt5}$ or about 3.24 seconds after it starts moving.

3 0

4 years ago

If red light hits a red filter, what kind of light comes through the filter?

Roman55 [17]

A. red, is the correct answer. A red filter only lets red light through, whether white or red light passes through it.
Hope this helps, and have a great day!

8 0

4 years ago

A person walks 2 miles every day to work, leaving her front porch at 7:00 A.M. and arriving at work at 7:30 A.M. ON the way home

Nataly [62]

Answer:

The displacement is zero miles

Explanation:

The displacement of an object that moves from point A to point B is defined as

$d =B-A$

Where d is the displacement of the object. The displacement does not depend on the trajectory of the object. It only depends on the linear distance between the end point and the starting point.

In this case we know that the person walks from home to work and then walks from work to home. Therefore, the total displacement is the linear distance between the point where its journey begins and the point where the route ends.

The tour begins on the front porch of your house and ends on the front porch of your house (when you return from work). If we call A to the front porch of the house then the displacement is:

$d = A-A = 0$

The displacement is zero miles, since the person finishes the journey just where it started (front porch)

7 0

3 years ago

What will be the average velocity of a body falling in free fall on Earth for 3 s?

SpyIntel [72]

Answer:

29.4m/s

Explanation:

Given parameters:

Time = 3s

Unknown:

Average velocity = ?

Solution:

To solve this problem, we use the expression below:

v = u + gt

v is the average velocity

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.8m/s²

t is the time

So;

v = 0 + (9.8 x 3) = 29.4m/s

6 0

3 years ago