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pshichka [43]
3 years ago
9

A car travels at a constant speed around a circular track whose radius is 2.9 km. the car goes once around the track in 400 s. w

hat is the magnitude of the centripetal acceleration of the car?
Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0
First we need the linear velocity 
<span> D=2*Pi*r=2*pi* 2.9=18.22 km=18,221.23m 
</span> V=D/T=18,221.23m/400s=<span> 45.55</span><span> m/s 
</span> A=V^2/r=(45.55 m/s)^2/2900m=<span> 0.72 </span><span>m/s^2 
</span> the magnitude of the centripetal acceleration of the car is 0.72 m/s^2 
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Answer:

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Step-by-step explanation:

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