The measurement of the largest square tile is 4 ft. by 4 ft.
You would need 6 of these tiles to fill the room.
I'm going to use the substitution method.
4x + 4y = -16
-8x - 6y = -20
4x + 4y = -16
- 4x - 4x
--------------------------
4y = -4x - 16
------ ------ ------
4 4 4
y = -x - 4
-8x - 6(-x - 4) = -20
-8x + 6x + 24 = -20
-2x + 24 = -20
- 24 - 24
----------------------------
-2x = 44
------- -------
2 2
x = 22
4(22) + 4y = -16
88 + 4y = -16
- 88 - 88
------------------------
4y = -104
------ ---------
4 4
y = -26
The answer is (22, -26).
<span>A)x-y+3 is your answer
Proof:
(5 x)/4 - 8 y - x/4 + 7 y + 3
Put each term in (5 x)/4 - 8 y - x/4 + 7 y + 3 over the common denominator 4: (5 x)/4 - 8 y - x/4 + 7 y + 3 = (5 x)/4 - (32 y)/4 - (x)/4 + (28 y)/4 + 12/4:
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4 = (5 x - 32 y - x + 28 y + 12)/4:
(5 x - 32 y - x + 28 y + 12)/4
Grouping like terms, 5 x - 32 y - x + 28 y + 12 = (28 y - 32 y) + (5 x - x) + 12:
((28 y - 32 y) + (5 x - x) + 12)/4
28 y - 32 y = -4 y:
(-4 y + (5 x - x) + 12)/4
5 x - x = 4 x:
(-4 y + 4 x + 12)/4
Factor 4 out of -4 y + 4 x + 12:
(4 (-y + x + 3))/4
(4 (-y + x + 3))/4 = 4/4×(3 + x - y) = 3 + x - y:
Answer: 3 + x - y
</span>
Answer:
The ordinate of B exceeds the ordinate of A by 7
Step-by-step explanation:
Let
A(x1,y1),B(x2,y2)
where
x1 is the abscissa of A
x2 is the abscissa of B
y1 is the ordinate of A
y2 is the ordinate of B
we know that
so
-----> equation A
----> equation B
substitute equation B in equation A
therefore
The ordinate of B exceeds the ordinate of A by 7
