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3 years ago

How to graph (-1,3).

Mathematics

2 answers:

iogann1982 [59]3 years ago

6 0

To first solve this you need to know that (X,Y) are the axis of the graph. So -1 is the X axis and 3 is the y axis

34kurt3 years ago

4 0

Over positive three and down 1. Hope it helps.

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Das has 3/4 of bottle of water.He drinks 3/8 of the bottle.How much of the bottle dose he have left?

sesenic [268]

Answer:

3/8

Step-by-step explanation

Convert 3/4 to 6/8 to make it easier subract since this problem asks how much he has left.

So 6/8-3/8=3/8

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3 years ago

Suppose a sample of 716 suspected criminals is drawn. Of these people, 286 were captured. Using the data, estimate the proportio

tamaranim1 [39]

Answer:

The proportion is p = 0.399

Step-by-step explanation:

The estimate of a proportion is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

286 people captured, so D = 286.

Total outcomes:

Sample of 716 suspected criminals, so T = 716.

Proportion

$p = \frac{286}{716} = 0.399$

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3 years ago

A gallon of gas costs $2.73. Walter pays for 24 gallons of gas. He gives the clerk $80.00. How much change should Walter receive

wolverine [178]

Answer:

14.48

Step-by-step explanation:

2.73×24=65.52 is how much 24 gallons cost.

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3 years ago

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3 years ago

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A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs

LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

$h=\frac{400}{\pi r^2}$

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: $h=\frac{400}{\pi r^2}$

Therefore:

$C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})$

$C(r)=0.12\pi r^2+\frac{24}{r}$

$C(r)=\frac{0.12\pi r^3+24}{r}$

The minimum cost occurs when the derivative of the Cost =0.

$C^{'}(r)=\frac{6\pi r^3-600}{25r^2}$

$6\pi r^3-600=0$

$6\pi r^3=600$

$\pi r^3=100$

$r^3=\frac{100}{\pi}$

$r^3=31.83$

r=3.17 cm

Recall that:

$h=\frac{400}{\pi r^2}$

$h=\frac{400}{\pi *3.17^2}$

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

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3 years ago