Answer: 1.3% many crosslinks as isoprene units,
Explanation:
Given:
mass pf natural rubber= 200.0g
mass of sulphur = 4.8g
molar mass of sulphur =32g/mol
molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol
Solution: we first find no of moles present in each using
no of moles = 
Isoprene: 200.0g x [1mole / 68g] = 2.94moles.
Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.
to find % crosslinked units, we have
0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,
B is the correct answer 9.0122
Answer:
Explanation:
Hello,
In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:
We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:
Thus, solving for the yielded volume of carbon dioxide we obtain:
Best regards.
Answer:
since 1 mole = 6.022×10^23
hence in 2.32 moles no. of atoms= 6.022×10^23 × 2.32
=
13.97104 ×10^23
plz mark it as brainliest
Answer:
A) 0.013 mol
Explanation:
B) The pressure will double.
