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____ [38]
3 years ago
14

Which of the ordered pairs below satisfy the following equation? Check all that apply. y = 7x A. (84, 12) B. (42, 7) C. (12, 84)

D. (84, 14) E. (6, 42)
Mathematics
1 answer:
Lana71 [14]3 years ago
5 0
C and e are the only ons correct
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Volunteer drivers are needed to bring 80 students to the championship
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Answer:

c=5 v=10

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3 years ago
The equation 3x + 2 = 29 is modeled below.
DanielleElmas [232]

Answer:

Subtract 2 from both sides.

Step-by-step explanation:

Remember to do the opposite of PEMDAS. PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

> Also, note the equal sign, what you do to one side, you do to the other side of the equation.

First step is to subtract 2 from both sides of the equation:

3x + 2 (-2) = 29 (-2)

3x = 29 - 2

3x = 27

The second step is to divide 3 from both sides of the equation:

(3x)/3 = (27)/3

x = 27/3

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7 0
3 years ago
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What percent is 45 out of 72?
Alenkinab [10]

Answer:

62.5%

Step-by-step explanation:

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3 years ago
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A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

6 0
3 years ago
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I need help on all these questions​
melamori03 [73]
1) 3/5
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7) 3/5
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10) -3/7
6 0
3 years ago
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