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lara31 [8.8K]
3 years ago
12

In a multiplicatication problem , if the first factor has 5 digits after a decimal after the decimal and second factor 4 decimal

, then the product will have ____ digits after the decimal
Mathematics
1 answer:
Rudiy273 years ago
5 0
The product will have 9 digits after decimals . This is because the number of decimal points are added in multiplication.
For eg. 2.5×2.5=6.25 , 0.5×0.5=0.25 .
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Where is the table? I would love to help!
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PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!In two or more complete sentences explain how you would set up and solve the following eq
olchik [2.2K]

Peter's account is 910-40x, and Marla's account is 470-2x. This is a system, so you must find the number that makes both equations end up with the same number. Basically trial and error. Here is what I did:

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Let's try 13 next. 910-520=390 and 470-26=444. Now the number has to be lower.

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4 0
3 years ago
Read 2 more answers
3/8n+5(n-6)=1 7/8n-2
ivann1987 [24]

Answer:

n = 112/13 = 8.615

Step-by-step explanation:

(3/8) n + 5n - 30 = (17/8)n - 2

(3/8)n +5n - (17/8)n = 30-2

(13/4)n = 28

n = 28 * 4/13

n = 112/13

n = 8.615

4 0
3 years ago
Two cyclists are 7 miles apart when they begin biking away from each other in
shutvik [7]

Answer:

25

Step-by-step explanation:

Its just 25

7 0
3 years ago
Please help me with this question
Setler [38]

Step-by-step explanation:

{ ({y}^{2} )}^{4} . \:  {( {y}^{3}) }^{2}

Since,

{ ({a}^{x} )}^{y}  =  {a}^{xy}

Hence,

{y}^{2 \times 4} . {y}^{3 \times 2}

=  {y}^{8} . {y}^{6}

Since,

{a}^{x} . {a}^{y}  =  {a}^{x + y}

Hence,

=  {y}^{8 + 6}

=  {y}^{14} (ans)

6 0
3 years ago
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