Answer:
2.5
Step-by-step explanation:
(I'm assuming you're doing this the same way I learned it, if not I'm sorry if it doesn't make sense)
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Cross multiply
12x=30
Divide
x=2.5
This is just one way to do the problem. An easier way is to simplify the fractions.
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You can either cross multiply or figure out that 2 is half of four and simply divide 5 by 2 which will also result in 2.5
Answer:
aUjJz slsmsmmwlakm
Step-by-step explanation:
nakaoianq s wkow9a9izjxi
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
It’s organized and you can see it more visually , gives you a way to double check and write down the data properly.
