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pychu [463]
3 years ago
13

After a security incident is verified in a SOC, an incident responder reviews the incident but cannot identify the source of the

incident and form an effective mitigation procedure. To whom should the incident ticket be escalated?
a SME for further investigation
a cyberoperations analyst for help
an alert analyst for further analysis
the SOC manager to ask for other personnel to be assigned
Computers and Technology
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

Option A i.e., SME for further investigation.

Explanation:

Following the reports of such a security incident into an SOC, an incident respondent examines the incident but could not determine the cause of that same incident as well as establish an appropriate response protocol. The ticket for an incident must be applied to SME for even more inquiry. So, the following answer is correct.

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Amtex Electronics, a consumer products brand, frequently advertises its products inside supermarkets and retail stores to promot
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Answer:

Amtex Electronics promotes the process of memory retrieval and stimulate purchase.

Explanation:

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For example, the memory of your son drinking juice is an example of retrieval. Memory had been stored in long- term memory.

Many types of memory retrieval are recall and recognition. This information must be retrieved from memories.

3 0
3 years ago
Historically, development of a new technology often:
andrew-mc [135]

Answer:

2. Leads to increases in productivity only once firms learn how to use it.

Explanation:

Technology is an all new or improved way of doing things to enhance effectiveness and efficiency that will lead to increase output. But the new technologies can not improve a business output if they don't grow with the trend of new technologies by updating their knowledge regularly

7 0
3 years ago
Read 2 more answers
What is the output when you run the following program? print(3 + 7) print("2 + 3")
QveST [7]

print(3+7) will output 10, which is an integer.

print("2+3") will output 2+3, which is a string.

6 0
3 years ago
What do digital signals tum sounds into?
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Digital signals turn sounds into analog signals
8 0
3 years ago
The running time of Algorithm A is (1/4) n2+ 1300, and the running time of another Algorithm B for solving the same problem is 1
Mnenie [13.5K]

Answer:

Answer is explained below

Explanation:

The running time is measured in terms of complexity classes generally expressed in an upper bound notation called the big-Oh ( "O" ) notation. We need to find the upper bound to the running time of both the algorithms and then we may compare the worst case complexities, it is also important to note that the complexity analysis holds true (and valid) for large input sizes, so, for inputs with smaller sizes, an algorithm with higher complexity class may outperform the one with lower complexity class i.e, efficiency of an algorithm may vary in cases where input sizes are smaller & more efficient algorithm might be outperformed by the lesser efficient algorithms in those cases.

That's the reason why we consider inputs of larger sizes when comparing the complexity classes of the respective algorithms under consideration.

Now coming to our question for algorithm A, we have,

let F(n) = 1/4x² + 1300

So, we can tell the upper bound to the function O(F(x)) = g(x) = x2

Also for algorithm B, we have,

let F(x) = 112x - 8

So, we can tell the upper bound to the function O(F(x)) = g(x) = x

Clearly, algorithmic complexity of algorithm A > algorithmic complexity of algorithm B

Hence we can say that for sufficiently large inputs , algorithm B will be a better choice.

Now to find the exact location of the graph in which algorithmic complexity for algorithm B becomes lesser than

algorithm A.

We need to find the intersection point of the given two equations by solving them:

We have the 2 equations as follows:

y = F(x) = 1/4x² + 1300 __(1)

y = F(X) = 112x - 8 __(2)

Let's put the value of from (2) in (1)

=> 112x - 8 = 1/4x² + 1300

=> 112x - 0.25x² = 1308

=> 0.25x² - 112x + 1308 = 0

Solving, we have

=> x = (112 ± 106) / 0.5

=> x = 436, 12

We can obtain the value for y by putting x in any of the equation:

At x=12 , y= 1336

At x = 436 , y = 48824

So we have two intersections at point (12,1336) & (436, 48824)

So before first intersection, the

Function F(x) = 112x - 8 takes lower value before x=12

& F(x) = 1/4x² + 1300 takes lower value between (12, 436)

& F(x) = 112x - 8 again takes lower value after (436,∞)

Hence,

We should choose Algorithm B for input sizes lesser than 12

& Algorithm A for input sizes between (12,436)

& Algorithm B for input sizes greater than (436,∞)

8 0
3 years ago
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