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astra-53 [7]
3 years ago
6

What is the algebraic expression for the difference between seven times a number and three times that number"?

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

the last one

Step-by-step explanation:

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Greatest to least 0.386;0.3;0.683;0.836
levacccp [35]
<span>Here you go .. ordered as you wish ..
0.836
</span><span>0.683
</span><span>0.386
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6 0
3 years ago
X2<br>2<br>ab<br>ab to<br>b<br>The diagian<br>K<br>n shows<br>rectangle. The shade<br>Find x.<br>​
Norma-Jean [14]

Answer:

x = 28 cm

Step-by-step explanation:

Given:

Area of link shaded regions = 84 cm²

Required:

The value of x (diameter of the semicircle/length of the rectangle)

Solution:

Diameter of the semicircle = 2r = x

Length of rectangle (L) = 2r = x

Radius of semicircle (r) = ½x

Width of rectangle (W) = radius of semicircle = ½x

Use 3.14 as π

Area of the link shaded regions = area of rectangle - area of semicircle

Thus:

Area of the link shaded regions = (L*W) - (½*πr²)

Plug in the values

84 = (x*½x) - (½*3.14*(½x)²)

84 = x²/2 - (1.57*x²/4)

84 = x²(½ - 1.57/4)

84 = x²(0.5 - 0.3925)

84 = x²(0.1075)

Divide both sides by 0.1075

84/0.1075 = x²

781.4 = x²

√781.4 = x

27.9535329 = x

x = 28 cm

5 0
3 years ago
Veronica wants to multiply
stira [4]

Answer:2737t

Step-by-step explanation:

5 0
3 years ago
Find the number of permutations of the first 9 letters of the alphabet, taking 4 letters at a time.
Vinil7 [7]

Solution-

First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I

Total number of ways of selection of 4 letters from 9 alphabets = 9C4

=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126

The number of ways of arranging these 4 numbers = 4! = 24

∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024

∴ option number 2 is correct.

8 0
4 years ago
Read 2 more answers
Plzzzzzzzzzzzzzzzz Helo <br>Answer correct please but It can tell if the answer is wrong ​
Setler79 [48]

Answer:

im pretty sure 20 seconds

Step-by-step explanation:

7 0
3 years ago
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