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3 years ago

The circumference of a circle is 121 3.14 cm, what is the area in term of pie

1 answer:

4 0

The circumference of a circle is determined by the formula 2πr.
I'd say divide the circumference by two and youll be left with 60.5=πr .
then divide 60.5 by 3.14 to get r
which is approximately 19.26
now use the circle formula for area
A=πr²
A in terms of pi is
A = π*(19.26)²

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Alex buys 5 DVDs. Each DVD costs $9. If Alex receives a $2 discount on each DVD, what is the total amount of money alex apends?

LekaFEV [45]

Answer:

The total amount of money Alex spends on 5 DVD = $ 35.

Step-by-step explanation:

Total number of DVD purchased by Alex = 5

The cost of each DVD = $9

So, the total cost of purchasing 5 DVD = 5 x ( csot of 1 DVD)

= 5 x ( $ 9) = $ 45

Now , the discount if 1 DVD = $ 2

So, the total discount of 5 DVD = 5 x ( Discount on1 DVD)

= 5 x ($ 2) = $ 10

⇒ The total amount Alex spends

= Total cost of 5 DVD - Discount on 5 DVD

= $ 45 - $ 10 = $ 35

Hence, the total amount of money Alex spends on 5 DVD = $ 35.

7 0

3 years ago

What is 8 2/3 - 1 3/10

just olya [345]

7 11/30

Hope this helped!

5 0

3 years ago

Read 2 more answers

Solve. Check for extraneous solutions. √2 x+6 - √x-1 =2

Alex

x = 5 is not an extraneous solution of the equation.

✓(2x + 6) - ✓(x - 1) = 2

✓(2x + 6) = 2 + ✓(x - 1)

Squaring both the sides of equation, we get

(✓(2x + 6))² = (2 + ✓(x - 1))²

2x + 6 = (2)² + (✓(x - 1))² + 2(2)(✓(x - 1))

2x + 6 = 4 + x - 1 + 4(✓(x - 1))

x + 3 = 4✓(x - 1)

Squaring again on both the side of the equation, we get

(x + 3)² = (4✓(x - 1))²

x² + 3² + 2×3×x = 16(x - 1)

x² + 9 + 6x = 16x - 16

x² - 10x + 25 = 0

By applying middle term splitting on equation (1), we get

x² - 5x - 5x + 25 = 0

x(x - 5) -5(x - 5) = 0

(x - 5) (x - 5) = 0

x = 5 and 5.

Check for extraneous solutions by putting value of x in original equation -

✓(2×5 + 6) - ✓(5 - 1) = 2

✓16 - ✓4 = 2

4 - 2 = 2

2 = 2

LHS = RHS

x = 5 is not an extraneous solution of the equation.

Know more about roots of equation -

brainly.com/question/4098861

#SPJ4

8 0

1 year ago

The sequence {an } is defined by a of o = 1 and a of n + 1 = 2 a of n + 2 for n = 0, 1, 2.... What is the value of a of 3?

maria [59]

$\begin{cases}a(0)=1\\a(n+1)=2a(n)+2&\text{for }n\ge0\end{cases}$

Use the second part of the definition (the recursive one):

$a(1)=2a(0)+2=4$
$a(2)=2a(1)+2=10$
$a(3)=2a(2)+2=22$

3 0

3 years ago

In an NBA championship series, the team that wins four games out of seven is the winner. Suppose that teams ???? and ???? face e

olchik [2.2K]

Answer:

a) P=0.185

b) P=0.608

c) P=0.593

Step-by-step explanation:

The question is not complete

"In an NBA championship series, the team that wins four games out of seven is the winner. Suppose that teams A and B face each other in the championship games and that team A has a probability 0.55 of winning a game over team B.

a. What is the probability that team A will win the series in 6 games?

b. What is the probability that team A will win the series?

c. If teams A and B were facing each other in a regional playoff series, which is decided by winning three out of 5 games, what is the probability that team A would win the series?

a) It is implicit that 6 games are played. The number of games needed to win a series in 6 games is 4, and the last winning should be in the 6th game.

So we have 5 random results in the first 5 games in which A team wins 3 matches and losses 2 matches.

This can be modeled as a binomial distribution with k=3, n=5 and p=0.55.

$P(k=3)=\frac{n!}{k!(n-k)!}p^k*(1-p)^{n-k}\\\\P(k=3)=\frac{5!}{3!2!}*0.55^3*0.45^2=10*0.166*0.203=0.337$

Then, this probability has to be multiplied by the probability of winning the last game.

$P(W_6)=P(k=3;n=5)*P(W_{6th})=0.337*0.55=0.185$

The probability that team A will win the series in 6 games is P=0.185.

b) In this case, we have to calculate the probability of A winning at least 4 games. When a team reaches 4 wins, the series is over. This can happen in 4, 5, 6 or 7 games.

The probability of winning the series is:

$P(W)=[P(3;3)+P(3;4)+P(3;5)+P(3;6)]*P(win\,last\,game)$

Probability of 3 wins in 3 games

$P(3;3)=\frac{3!}{3!0!}*0.55^3*0.45^0 =1*0.166*1=0.166$

Probability of 3 wins in 4 games

$P(3;4)=\frac{4!}{3!1!}*0.55^3*0.45^1 =4*0.166*0.45=0.299$

Probability of 3 wins in 5 games

$P(3;5)=\frac{5!}{3!2!}*0.55^3*0.45^2 =10*0.166*0.203=0.337$

Probability of 3 wins in 6 games

$P(3;6)=\frac{6!}{3!3!}*0.55^3*0.45^3 =20*0.166*0.091=0.303$

Then

$P(W)=[P(3;3)+P(3;4)+P(3;5)+P(3;6)]*P(win\,last\,game)\\\\P(W)=[0.166+0.299+0.337+0.303]*0.55=1.105*0.55=0.608$

The probability of team A of winning the series is P=0.608.

c) The probabilty of winning the regional playoff is

$P(W)=[P(2;2)+P(2;3)+P(2;4)]*P(win\,last\,game)$

$P(2;2)=\frac{2!}{2!0!}*0.55^2*0.45^0 =1*0.303*1=0.303\\\\P(2;3)=\frac{3!}{2!1!}*0.55^2*0.45^1 =3*0.303*0.45=0.408\\\\P(2;4)=\frac{4!}{2!2!}*0.55^2*0.45^2 =6*0.303*0.203=0.368$

Then,

$P(W)=[P(2;2)+P(2;3)+P(2;4)]*P(win\,last\,game)\\\\P(W)=[0.303+0.408+0.368]*0.55=1.079*0.55=0.593$

8 0

3 years ago