Question

HELP PLEASE!!

Answer 1

1. The probability distribution table shows the proportion of people living in the five different regions of a city.

The probabiliy that a person randomly selected lives in the west region is 0.2. Let x be the number of people that live in the west region. Then

$\dfrac{x}{46,700}=0.2,\\ \\x=46,700\cdot 0.2=9,340.$

Answer 1: correct hcoice is D

2. The probability that a person chosen at random lives in the central or south region is

$Pr(\text{central or south})=Pr(\text{central})+Pr(\text{south})=0.44+0.14=0.58.$

Answer 2: correct choice is A

Answer 2

For number one the answer is D. 9340
for number two the answer is B. 0.44