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3 years ago

List three responsibilities of a minister.

Engineering

2 answers:

sweet-ann [11.9K]3 years ago

6 0

Answer:

Minister's responsibilities are given in the explanation section below.

Explanation:

The Ministry seems to be responsible for both the curriculum as well as the guidance of any internationally endorsed middle and high schools in the provincial capital as well as some just outside of the provincial capital.
A minister's main responsibility would be to distribute preaching to the religious community on something like a weekly basis.
The Ministry also becomes necessary for national several independent teacher unions throughout Ontario and therefore is not active in day-to-day procedures.

kifflom [539]3 years ago

6 0

Spiritual leadership involves being leader of religious services, being a teacher, creator and leader of religious programs, and articulating a vision for the congregation.

The pastoral role involves pastoral counseling, bereavement counseling, performing weddings and funerals, and similar roles.

The third role, that of administrator, will be explained in more detail. The Minister is a facilitative administrator in most areas of his work. This means the Minister will:

Help facilitate the work of the duly-elected leaders of the congregation in running the church.
Help church leaders define and create processes that aid church work and governance.
Help people be more effective leaders
Encourage the idea that the responsibility of leading the church rests with the members themselves.
Engage in conflict resolution and consensus building among persons, groups,
committees, and groups within committees, about issues needing this service.

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Design complementary static CMOS circuits with minimized number of transistors to realize the following Boolean functions (hint:

Pie

Answer:

as pull up network. the metteing point of pull down and pull up is the point where we take the output

note 1: if two n-mos are connected in series it gives logical AND and p-mos paralle gives logical-AND

note 2: if two n-mos are connected in parallel it gives logical OR and p-mos series gives logical-OR

note 3: output is always complement of what we implement

example Y= (AB)'

image attached

A) F = (ABC + D(A+B) )'

pulldown:

this can be realize by takeing three n-mos in series which gives ABC ,two n-mos are parallel which in series with another n-mos whic gives D(A+B), now connect ABC and D(A+B) in parallel

pull up

this can be realize by takeing three p-mos in parallel which gives ABC ,two p-mos are series which is in serires with

another p-mos whic gives D(A+B), now connect ABC and D(A+B) in series

the out put will be (ABC + D(A+B) )'

so we require total 6-mos and 6-pmos total 12mos transistors

B) F = AC + BD

pull down

this can be realize by takeing two n-mos in series which gives AB ,two n-mos are in series

which whic gives BD, now connect AC and BD in parallel

pull up

this can be realize by takeing two p-mos in parallel which gives Ac ,two p-mos are in parallel

which whic gives BD, now connect AC and BD in series

the output is (AC+BD)'

to avoid the complement we have to connect the output to c-mos inverter then we get AC+BD

so we require 5-nmos, 5-pmos total 10 mos transistors

8 0

3 years ago

Filler metals range in diameter from 1/16" to 3/8"*<br> O<br> true<br> O False

vesna_86 [32]

Answer:

O False

Explanation:

Can you make me the brainliest pls, thx.

6 0

3 years ago

At a point on the free surface of a stressed body, the normal stresses are 20 ksi (T) on a vertical plane and 30 ksi (C) on a ho

victus00 [196]

Answer:

The principal stresses are σp1 = 27 ksi, σp2 = -37 ksi and the shear stress is zero

Explanation:

The expression for the maximum shear stress is given:

$\tau _{M} =\sqrt{(\frac{\sigma _{x}^{2}-\sigma _{y}^{2} }{2})^{2}+\tau _{xy}^{2} }$

Where

σx = stress in vertical plane = 20 ksi

σy = stress in horizontal plane = -30 ksi

τM = 32 ksi

Replacing:

$32=\sqrt{(\frac{20-(-30)}{2} )^{2} +\tau _{xy}^{2} }$

Solving for τxy:

τxy = ±19.98 ksi

The principal stress is:

$\sigma _{x}+\sigma _{y} =\sigma _{p1}+\sigma _{p2}$

Where

σp1 = 20 ksi

σp2 = -30 ksi

$\sigma _{p1} +\sigma _{p2}=-10 ksi$ (equation 1)

$\tau _{M} =\frac{\sigma _{p1}-\sigma _{p2}}{2} \\\sigma _{p1}-\sigma _{p2}=2\tau _{M}\\\sigma _{p1}-\sigma _{p2}=32*2=64ksi$ equation 2

Solving both equations:

σp1 = 27 ksi

σp2 = -37 ksi

The shear stress on the vertical plane is zero

4 0

4 years ago

A material point in equilibrium has 1 independent component of shear stress in the xz plane. a)True b)- False

ozzi

Answer:

True

Explanation:

For point in xz plane the stress tensor is given by $\left[\begin{array}{ccc}Dx_{} &txz\\tzx&Dz\\\end{array}\right]$

where Dx is the direct stress along x ; Dz is direct stress along z ; tzx and txz are the shear stress components

We know that the stress tensor matrix is symmetrical which means that tzx = txz ( obtained by moment equlibrium )

thus we require only 1 independent component of shear stress to define the whole stress tensor at a point in 2D plane

8 0

3 years ago

Pls hurry

sergey [27]

Answer:The answer is Potassium!

Explanation: This is true because each label should tell you about the available amount of a certain element. The standard order is Nitrogen-Phosphorus-Potassium. They are referred to by their standard abbreviations in the periodic table. One problem with fertilizer labels are that they are only required to disclose the amounts of macronutrients (or Nitrogen-Phosphorus-Potassium.)

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3 years ago