Answer:
Below is the response to the given question:
Explanation:
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Answer:
work done by electric field is 0.06 J
Explanation:
Given data:
Two point charge is 
0+1 charge positioned is (0 cm , 1 cm, 0.00 cm)
-1 charge positioned is (0 cm , -1 cm, 0.00 cm)
E = 3.0\times 10^6 N/C
From above information, the distance between given two charges d = 2 cm
then d = 0.02m
work needed is W = q E d

W = 0.06 J
Therefore work done by electric field is 0.06 J
Answer:
a) no roots not in LHP
b) 2 roots not in LHP
c) 2 roots not in the LHP
d) 2 roots not in the LHP
e) 2 roots not in LHP
Explanation:

No roots not in the LHP

2 roots not in the LHP

There are roots in the RHP (not all coefficients are greater than 0).
2 roots not in the LHP

There are two sign changes in the first column of the Routh array.
2 roots not in the LHP

2 roots not in LHP
check:
⇒

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Answer:
b. 2.3 kPa.
Explanation:
This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

Where:
,
- Pressures at the beginning and at the end of the current line, measured in kilopascals.
- Water density, measured in kilograms per cubic meter.
,
- Fluid velocity at the beginning and at the end of the current line, measured in meters per second.
Now, the pressure difference between these two points is:

If
,
and
, then:


(1 kPa is equivalent to 1000 Pa)
Hence, the right answer is B.