Answer:
Enthalpy
Explanation:
Thermodynamic properties could be Intensive or extensive properties. Intensive properties are those that don't depend on the quantity of matter. Examples are pressure & temperature. Meanwhile, extensive properties are those whose values depend on the mass of the system. Examples are Energy, enthalpy and volume.
Now, in turbines in thermodynamics, the work done is produced by the flow required to turn the turbine and shaft. Recall that from the law of conservation of energy, the work in the turbine per mass airflow would be equal to the change in specific enthalpy of the flow from the entrance to the exit point of the turbine.
Thus, the property required to determine the work is Enthalpy.
Answer:
electric potential = 22.36 volt
Explanation:
given data
charge Q = 11.748 nC
distance d = 5 - 2 = 3 m
length = 2 + 2 = 4 m
Coulomb constant = 8.98755 × 109 N·m²/C ²
solution
electric potential is express as
electric potential = 
..............1
electric potential = 
put here value
electric potential = 
electric potential = 22.36 volt
Answer:
Using linkedlist on C++, we have the program below.
Explanation:
#include<iostream>
#include<cstdlib>
using namespace std;
//structure of linked list
struct linkedList
{
int data;
struct linkedList *next;
};
//print linked list
void printList(struct linkedList *head)
{
linkedList *t=head;
while(t!=NULL)
{
cout<<t->data;
if(t->next!=NULL)
cout<<" -> ";
t=t->next;
}
}
//insert newnode at head of linked List
struct linkedList* insert(struct linkedList *head,int data)
{
linkedList *newnode=new linkedList;
newnode->data=data;
newnode->next=NULL;
if(head==NULL)
head=newnode;
else
{
struct linkedList *temp=head;
while(temp->next!=NULL)
temp=temp->next;
temp->next=newnode;
}
return head;
}
void multiplyOddPosition(struct linkedList *head)
{
struct linkedList *temp=head;
while(temp!=NULL)
{
temp->data = temp->data*10; //multiply values at odd position by 10
temp = temp->next;
//skip odd position values
if(temp!= NULL)
temp = temp->next;
}
}
int main()
{
int n,data;
linkedList *head=NULL;
// create linked list
head=insert(head,20);
head=insert(head,5);
head=insert(head,11);
head=insert(head,17);
head=insert(head,23);
head=insert(head,12);
head=insert(head,4);
head=insert(head,21);
cout<<"\nLinked List : ";
printList(head); //print list
multiplyOddPosition(head);
cout<<"\nLinked List After Multiply by 10 at odd position : ";
printList(head); //print list
return 0;
}
Answer:
451 kj/kg
Explanation:
Velocity = 139m/s
Temperature = 70⁰C
T = 343K
M1 = v/√prt
= 130/√1.4x287x343
= 130/√137817.4
= 130/371.2
= 0.350
T1/To1 = 0.9760
From here we cross multiply and then make To1 the subject of the formula
To1 = T1/0.9760
To1 = 343/0.9760
To1 = 351.43
Then we go to the rayleigh table
At m = 0.35
To1/To* = 0.4389
To* = 351.43/0.4389
= 800k
M2 = 1
Maximum amount of heat
1.005(800-351.43)
= 450.8kj/kg
= 452kj/kg
