Easy just do the negitive numbers and then try to add to the greates number
Your answer is 158 hope this helps.
Answer:
which is an irrational number
Step-by-step explanation:
Recall that the repeating decimal 0.7373737373... can be written in fraction form as: ![\frac{73}{99}](https://tex.z-dn.net/?f=%5Cfrac%7B73%7D%7B99%7D)
Now, let's write the number 147 which is inside the square root in factor form to find if it has some perfect square factors:
![147=7^2\,3](https://tex.z-dn.net/?f=147%3D7%5E2%5C%2C3)
Then, 7 will be able to go outside the root when we compute the final product requested:
![\frac{73}{99} \,*\,7\,\sqrt{3} =\frac{511\,\,\sqrt{3} }{99}](https://tex.z-dn.net/?f=%5Cfrac%7B73%7D%7B99%7D%20%5C%2C%2A%5C%2C7%5C%2C%5Csqrt%7B3%7D%20%3D%5Cfrac%7B511%5C%2C%5C%2C%5Csqrt%7B3%7D%20%7D%7B99%7D)
This is an irrational number due to the fact that it is the product of a rational number (quotient between 511 and 99) times the irrational number ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Your answer is going to be 23/22