Ask question

Ask question

All categories

2 years ago

11

Look at the figure below: A circle is shown with the center O. OP is a segment joining center O to a point P on the circle. MN i

s a line touching the cir Which is the tangent to the circle? (Segment OP Line ST Line MN Segment QR

2 answers:

Ivahew [28]2 years ago

4 0

It should be line MN

QveST [7]2 years ago

3 0

Answer:

line mn

Step-by-step explanation:

You might be interested in

Max earns $9.30 per hour does part time job how much money will max earn if he works 1,5,8,H hours also how many hours will he w

nataly862011 [7]

Step-by-step explanation:

write a formula that models this.

9.30x = money earned

If he works 2 hours, he'll get $9.30 times (2)

and so on. so you write and solve

9.30(1), 9.30(5), 9.30(8)

for the second part you want to substitute 180 for the amount earned which will become

9.30x = 180 then you solve for x

3 0

2 years ago

X =<br> 95<br> (7x - 4)<br> (3x + 23)°<br> (9x – 6)

anygoal [31]

Answer:

661 is for the first 308 for second 849 for last

Step-by-step explanation:

3 0

2 years ago

Marie buys 16 bags of potting soil that comes in 5 - 8 pound bags. If Marie's father calls and he needs 13 pounds of potting soi

vesna_86 [32]

One bag of 5 pounds and one bag of 8 pounds

4 0

2 years ago

In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat

monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

$f(t) = 10000(0.9407)^t$

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

$f(t) = f(0)(1-r)^t$

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that $f(0) = 10000$ , thus:

$f(t) = 10000(1-r)^t$

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

$f(2) = 8850$

We use this to find 1 - r.

$f(t) = 10000(1-r)^t$

$8850 = 10000(1-r)^2$

$(1-r)^2 = \frac{8850}{10000}$

$(1-r)^2 = 0.885$

$\sqrt{(1-r)^2} = \sqrt{0.885}$

$1 - r = 0.9407$

Thus

$f(t) = 10000(1-r)^t$

$f(t) = 10000(0.9407)^t$

7 0

2 years ago

If you’re good with permutations in math 30 please help and answer this easy question below real answers only

Len [333]

Answer: d) 2730

<u>Step-by-step explanation:</u>

1st movie and 2nd movie and 3rd movie

15 videos × 14 remaining videos × 13 remaining videos = 2730

6 0

3 years ago