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Gemiola [76]
3 years ago
9

What is the simplest form of this expression -x(7x+2)+x^2

Mathematics
2 answers:
kodGreya [7K]3 years ago
7 0
 The answer would be  -6x ^ 2 - 2x
Equation:
=-x (7x + 2) + x ^ 2
 =(-7x ^ 2 -2x) + x ^ 2
Add similar terms,
 -6x ^ 2 - 2x

 
The simplified expression is given by:
 
-6x ^ 2 - 2x
STALIN [3.7K]3 years ago
5 0
For this case we have the following expression:
 -x (7x + 2) + x ^ 2
 Rewriting we have:
 (-7x ^ 2 -2x) + x ^ 2
 Adding similar terms we have:
 -6x ^ 2 - 2x
 Answer:
 
The simplified expression is given by:
 
-6x ^ 2 - 2x
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G(x) = 4x + 4<br> F(x)=3/5x - 9/5
Wittaler [7]

Answer:

need more info

Step-by-step explanation:

7 0
3 years ago
1. Write the interval shown on the number line
shusha [124]

Answer:

x\geq 5

\{x\  |\  x \geq 5\}   OR {5, 6, 7, 8, .....}

Step-by-step explanation:

First of all, let us have a look at the interval shown on the number line and try to understand it properly.

The number line shows positive numbers starting from 3 that means numbers indicated will be positive numbers.

The number highlighted starts from 5 and there is filled circle at 5.

So, 5 is included in the interval.

The arrow is from 5 towards 8 and so on..

That means Numbers greater than or equal to 5 are represented by the interval.

So, writing as an inequality

Let x represents one of the numbers.

Hence, inequality can be written as:

x\geq 5

Using the set notation:

\{x\  |\  x \geq 5\}

OR

{5, 6, 7, 8, .....}

3 0
3 years ago
How do i solve 2x+7=x+11
juin [17]
Put the x on one side 
2x+7=x+11
-x      -x
x+7=11
Then subtract
x+7-7=11-7
x=4
Hope it helps!!
6 0
3 years ago
A parallelogram is
gavmur [86]
The correct answer to this question is B. Hope this helps :)
3 0
3 years ago
A sequence of three real numbers forms an arithmetic progression with a first term of 9. If 2 is added to the second term and 20
Alexxandr [17]

Answer:

The smallest possible value for the third term of the geometric progression is 1.

Step-by-step explanation:

Given : A sequence of three real numbers forms an arithmetic progression with a first term of 9. If 2 is added to the second term and 20 is added to the third term, the three resulting numbers form a geometric progression.

To find : What is the smallest possible value for the third term of the geometric progression?  

Solution :

The arithmetic progression is given by a,a+d,a+2d

First term a=9

Second term - 2 is added to second term i.e. a+d+2=9+d+2=11+d

Third term - 20 is added to the third term i.e.a+2d+20=9+2d+20=29+2d

The geometric progression is given by a,ar,ar^2

First term a=9

Second term -ar=11+d

Third term ar^2=29+2d

r is the common ratio which is second term divided by first term,

So, r=\frac{ar}{a}=\frac{11+d}{9}

or  third term divided by second term,

So, r=\frac{ar^2}{ar}=\frac{29+2d}{11+d}

Equating both the r,

\frac{11+d}{9}=\frac{29+2d}{11+d}

Cross multiply,

(11+d)\times (11+d)=(29+2d)(9)

11^2+11d+11d+d^2=261+18d

121+22d+d^2-261-18d=0

d^2+4d-140=0

Solving by middle term split,

d^2+14d-10d-140=0

d(d+14)-10(d+14)=0

(d+14)(d-10)=0

d=-14,10

Substituting the value of d in the third term,

Third term ar^2=29+2d

When d=-14,

Third term ar^2=29+2(-14)=29-28=1

When d=10,

Third term ar^2=29+2(10)=29+20=49

Therefore, The smallest possible value for the third term of the geometric progression is 1.

7 0
3 years ago
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