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igor_vitrenko [27]
4 years ago
5

SOMEBODY PLEEEAAASE HELP ME!!

Physics
2 answers:
deff fn [24]4 years ago
8 0

Answer:

is 2.2

Explanation:

Andreas93 [3]4 years ago
5 0
For A Brainliest Plz? Here is the Answer:
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How many neutrons is there in that element that has 36 protons and 36 electrons
bagirrra123 [75]
You need to know the mass number to work it out. I can see you have it but it's not visible on your photo.

Every proton weighs 1 and every neutron weighs 1 so if you know the total mass of the nucleus and the number of protons, then you can do:
Mass Number - Proton Number = Neutron Number
because the rest of the mass (that isn't from the protons) must come from the neutrons. Make sense?
3 0
3 years ago
E. An object is thrown from the top of a tower with
bearhunter [10]

Answer:

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Explanation:

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3 years ago
What is the wavelength, in nm, of a photon with energy
lara31 [8.8K]

Answer:

(a)  λ = 4136 nm → infrared

(b) λ = 413.6 nm → visible light

(c) λ = 41.36 nm → ultraviolet

Explanation:

The wavelength of infrared is on the range of 700 nm to 1000000 nm

The wavelength of visible light is between 400 nm and 700 nm

The wavelength of ultraviolet ray on the range of 10 nm to 400 nm

The wavelength of photon is given by;

E = hf

f is the frequency of the wave = c / λ

E = h\frac{c}{\lambda}\\\\ \lambda = \frac{hc}{E}

Where;

c is the speed of light = 3 x 10⁸ m/s

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

(a) 0.3 eV = 0.3 x 1.602 x 10⁻¹⁹ J

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(0.3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-6} \ m

λ = 4136 x 10⁻⁹ m

λ = 4136 nm → infrared

(b) 3.0 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-7} \ m

λ = 413.6 x 10⁻⁹ m

λ = 413.6 nm →visible light

(c) 30 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(30)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-8} \ m

λ = 41.36 x 10⁻⁹ m

λ = 41.36 nm →ultraviolet

5 0
3 years ago
The energy of a photon is equal to (what) times (what) of the photon.
hjlf

The energy carried by a photon is equal to

(Planck's Konstant) times (the frequency of the photon) .

Planck's konstant is 6.626 x 10⁻³⁴ m²-kg/s  (rounded)

3 0
3 years ago
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Predict how heat would flow if beaker A is moved so that it's touching beaker B A. Heat would flow from beaker B to beaker A. B.
jek_recluse [69]
Zeroth Law of Thermodynamics, which in turn will mean the heat will transfer between both of them up to the point where they are in thermodynamic equilibrium. So the answer is C.
6 0
3 years ago
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