Answer:
second force = 32.784
Magnitude =
θ = -90°
Explanation:
a)
Fnet = ma
F1 + F2 = ma
20N + F2 = 2(12 × cos30° + 12 ×sin30°)
F2 = 2 × 12 ( sin 30° + cos 30°)
= 24 × ( 1 + √3 )÷ 2
=12 (1 +√3 )
= 32.784
b)

= 
= 
=
c)
θ = 30° + 180°
θ = 210°
210° - 300°
θ = -90°
As per impulse momentum theorem we know that

now here we will have

t = 1.30 ms
m = 0.144 kg

now we need to find final speed using above formula


so final speed is given as above
The work W needed to stretch/compress a spring from rest by a distance x is
W = 1/2 kx²
where k is the spring constant.
This means the work needed to change the length of this spring by 10 cm = 0.01 m is
W = 1/2 (200 N/m) (0.01 m)² = 0.01 J
and by 15 cm = 0.015 m is
W' = 1/2 (200 N/m) (0.015 m)² = 0.0225 J
Then the total work performed on the spring by stretching from 10 cm to 15 cm is
∆W = W' - W = 0.0225 J - 0.01 J = 0.0125 J
Answer:
my dad is a physics professor so when he comes home i will tell him to answer the question for you
Answer:
The combined velocity is 8.61 m/s.
Explanation:
Given that,
The mass of a truck, m = 2800 kg
Initial speed of truck, u = 12 m/s
The mass of a car, m' = 1100 kg
Initial speed of the car, u' = 0
We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

So, the combined velocity is 8.61 m/s.