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4 years ago

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A car travels from point A to point B, moving in the same direction but with a non-constant speed. The first half of the distanc

e, the car travels with a speed v 1 â.The remaining part of the way, the car travels half the time with a speed v2 ââand half the time with a speed v3 ââ . What is the average speed over the entire journey?

1 answer:

Dmitrij [34]4 years ago

6 0

Answer:

Explanation:

From A to B

distance traveled with velocity $v_1$ in time $t_1$

$\frac{d}{2}=v_1t_1----1$

from B to C

distance traveled is 0.5 d with $v_2$ and $v_3$ velocity for half-half time

$\frac{d}{2}=\frac{v_2t_2}{2}+\frac{v_3t_3}{2}----2$

divide 1 and 2 we get

$\frac{1}{1}=\frac{2v_1t_1}{v_2t_2+v_3t_3}$

$\frac{t_1}{t_2}=\frac{v_2+v_3}{2v_1}$

Now average velocity is given by

$v_{avg}=\frac{d}{t_1+t_2}$

taking $t_1$ common

$v_{avg}=\frac{2v_1t_1}{t_1(1+\frac{t_2}{t_1})}$

$v_{avg}=\frac{2v_1}{1+\frac{2v_1}{v_2+v_3}}$

$v_{avg}=\frac{2v_1(v_2+v_3)}{2v_1+v_2+v_3}$

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The overall final velocity of this projectile will be:

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Divide the change in velocity by acceleration (rate of change in velocity) to find the time required to achieve such change:

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