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attashe74 [19]
4 years ago
9

While wearing rubber-soled shoes, you rub a helium balloon on your sweater. the balloon becomes negative charged. now release th

e balloon. when the balloon is at the ceiling, you are
Physics
1 answer:
Alex17521 [72]4 years ago
8 0
You are effectively creating static electricity.
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A block of weight 45.7 N is hanging from a rope. The tension from the rope is pulling upward on the block. The block is accelera
viktelen [127]
<h2>Answer:</h2><h2></h2>

52.555 N

<h2>Explanation:</h2>

Let's use Newton's second law of motion here which states that the resultant force (∑F) acting on a body is the product of the mass (m) of the body and the acceleration (a) due to this force. i.e

∑F = m x a            ---------------------(i)

<em>Now, let's get the resultant force;</em>

Two main forces are acting on the rope;

i. the weight (W) of the block acting downwards.

Where;

W = mass of block(m) x gravity(g) = m x g

ii. the tension (T) in the rope acting upwards.

Therefore, the resultant force is the vector sum of these two forces as follows;

∑F = - W + T            [upward motion is taken as positive. hence -W and +T]

<em>Substitute ∑F = - W + T into equation (i) as follows;</em>

- W + T = m x a      ---------------------(ii)

<em>From the question;</em>

* Weight (W) of the block = 45.7N

=> mass (m) of the block = W / g = 45.7 / 10               [Taking g = 10m/s²]

=> m = 4.57 kg

* acceleration (a) = 1.50m/s²

<em>Substitute these values into equation (ii) as follows;</em>

- 45.7 + T = 4.57 x 1.50

- 45.7 + T = 6.855

<em>Solve for T;</em>

T = 6.855 + 45.7

T = 52.555 N

Therefore, the tension in the rope is 52.555 N

   

6 0
4 years ago
7. Two bikes travelling in the same direction move at a speed of 30 km/hr. The bikes are separated by a distance of 5 km. What w
Fantom [35]

Answer:

Explanation:

Call the bike on the right A

Call the bike on the left B

The car begins it's time when it passes A

4 minutes later, it passes B.

But B has moved in 4 minutes and that is the key to the problem.

How far has B moved.

t = 4 minutes = 4/60 hours = 1/15 of an hour.

d = ?

rate = 30 km / hr

d = r * t

d = 30 km/hr * 1/15 hours = 2 km

The distance between the bikes is 5 km.

So the car has traveled 5 - 2 = 3 km

d = 3 km

r = ?

t = 4 minutes = 1/15 hour

r = d/t = 3/(1/15)= 3 / 0.066666666  = 45 km/hr.

6 0
4 years ago
a banana boat accelerates from 4.167 m/s ar 2.00m/s^2.How far has it traveled when it reaches 8.333 m/s
Nataly_w [17]

Answer: The distance that we'll be travelled is d=16.35m

Explanation: The main idea here is to use the equation of motion. We are given the acceleration of 2m/s^2,the initial and final velocies. The formula to use is v^2=u^2+2as. Now we have to substitute the values.

2^2= 8.33^2+2(2)d

d= 16.35m

8 0
4 years ago
A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the gr
k0ka [10]

This question is incomplete, the complete question is;

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum (λ=520nm) is I, find the intensity (in terms of I) of scattered light

a) In the middle of the red part of the spectrum (λ= 665 nm)

b) In the middle of the violet part of the spectrum (λ = 420 nm)

Answer:

a) the intensity of scattered light ( in terms of I ) In the middle of the red part of the spectrum is 0.3739I

b) the intensity of scattered light ( in terms of I ) In the middle of the violet part of the spectrum is 2.3497I  

Explanation:

Given the data in the question,

the visible spectrum (λ=520nm) = I

we know that; intensity of scattered light is proportional to 1 / λ⁴  

I ∝ ( 1 / λ⁴ )

so

a)

I_R / I = ( λ / λ_R )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ_R is 665 nm

we substitute

I_R / I = ( 520 / 665 )⁴

I_R / I = ( 0.781954887 )⁴

I_R / I = 0.3739

I_R  =  0.3739I  { in terms of I  }

Therefore, the intensity of scattered light ( in terms of I ) In the middle of the red part of the spectrum is 0.3739I

b)

I_V / I = ( λ / λ_V )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ_R is 420 nm

we substitute

I_V / I = ( 520 / 420 )⁴

I_V / I = ( 1.238095 )⁴

I_V / I = 2.3497

I_V = 2.3497I  { in terms of I  }

Therefore, the intensity of scattered light ( in terms of I ) In the middle of the violet part of the spectrum is 2.3497I  

5 0
3 years ago
Read 2 more answers
1 point
avanturin [10]

Answer:

D. The water on her skin evaporates quickly and cools her skin.

Explanation:

7 0
4 years ago
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