Question

If f(x) = - x2 + 6x - 1 and g(x) = 3x2 - 4x - 1, find (f- g)(x).

Answer 1

Answer:

Step-by-step explanation:

- 4x² + 10x

Answer 2

Answer:

$\fbox{\begin{minipage}{11em}(f - g)(x) = -2x(2x - 5)\end{minipage}}$

Step-by-step explanation:

Given:

$f(x) = -x^{2} + 6x - 1 \\ g(x) = 3x^{2} - 4x - 1$

Solve for:

$(f - g)(x)$

Solution:

Perform the subtraction:

$(f - g)(x) = (-x^{2} + 6x - 1) - (3x^{2} - 4x - 1)$

Eliminate the parenthesis (notice the change in sign of some components):

$(f - g)(x) = -x^{2} + 6x - 1 - 3x^{2} + 4x + 1$

Rearrange the expression:

$(f - g)(x) = (-x^{2} - 3x^{2}) + (6x + 4x) + (1 - 1)$

Simplify the expression:

$(f - g)(x) = -4x^{2} + 10x$

Perform the inverse of associative property:

$(f - g)(x) = -2x(2x - 5)$

Hope this helps!

:)