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polet [3.4K]
3 years ago
10

If f(x) = - x2 + 6x - 1 and g(x) = 3x2 - 4x - 1, find (f- g)(x).

Mathematics
2 answers:
ElenaW [278]3 years ago
3 0

Answer:

Step-by-step explanation:

- 4x² + 10x

maria [59]3 years ago
3 0

Answer:

\fbox{\begin{minipage}{11em}(f - g)(x) = -2x(2x - 5)\end{minipage}}

Step-by-step explanation:

<em><u>Given:</u></em>

f(x) = -x^{2} + 6x - 1 \\ g(x) = 3x^{2} - 4x - 1\\

<em><u>Solve for: </u></em>

(f - g)(x)

<em><u>Solution:</u></em>

Perform the subtraction:

(f - g)(x) = (-x^{2} + 6x - 1) - (3x^{2} - 4x - 1)

Eliminate the parenthesis (notice the change in sign of some components):

(f - g)(x) = -x^{2} + 6x - 1 - 3x^{2} + 4x + 1

Rearrange the expression:

(f - g)(x) = (-x^{2} -  3x^{2}) + (6x + 4x) + (1 - 1)

Simplify the expression:

(f - g)(x) = -4x^{2} + 10x

Perform the inverse of associative property:

(f - g)(x) = -2x(2x - 5)

Hope this helps!

:)

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Answer:

The graph is attached below.

Step-by-step explanation:

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7 0
3 years ago
Please help me with these two math problems that I do not quite understand. This is urgent!
g100num [7]

Answer:

1)a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19

2) a_{10}=4+8(10-1)\Rightarrow a_{10}=76

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.

<em>"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"</em>

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2)  is already an Explicit Formula, since it is given the first term a_{1}=-1 the common difference d=-2 let's find some terms of this Sequence through this Explicit Formula:

a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19

2) (4,12,20,28, ..) In this Arithmetic Sequence the common difference is 8, the first term value is 4.

Then, just plug in the first term and the common difference into the explicit formula:

a_{10}=4+8(10-1)\Rightarrow a_{10}=76

6 0
2 years ago
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