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vodka [1.7K]
3 years ago
9

Choose the correct equation to represent the following statement (unbalanced chemical equation): ethane reacts with oxygen to yi

eld carbon dioxide and liquid water.
a.c2h6 (
g. o2(
g. co2(l) h2o(
g.
b.c2h6 (
g. o2(
g. co2(
g. h2o(l)
c.c2h6 (
g. o2(
g. co(
g. h2o(l)
d.c2h6 (
g. co2(
g. o2(
g. h2o(l)
Chemistry
2 answers:
Troyanec [42]3 years ago
8 0
<span>Ethane reacts with oxygen to yield carbon dioxide and liquid water. I believe the correct answer from the choices listed above is option B. The correct equation for this reaction would be as follows:

</span><span>c2h6 (g) + o2(g) = co2(g) + h2o(l)

Hope this answers the question. Have a nice day.</span>
FrozenT [24]3 years ago
5 0

Answer:

The correct answer option b.

Explanation:

When ethane reacts with oxygen it gives water and carbon-dioxide gas.This type of chemical reaction is called Combustion reaction.

C_2H_6(g)+\frac{7}{2}O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)

Since, in all the options equation is unbalanced.So , the correct answer is option b.

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B. elements
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A solid object has a mass of 1.62 lb and a volume of 190 mL.
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The density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.

<h3>How to calculate density?</h3>

Density is the measure of the mass of matter contained by a unit volume. It can be calculated by dividing the mass of the substance by its volume.

According to this question, a solid object is said to have a mass of 1.62 lb and a volume of 190 mL.

1 pound = 453.592 grams

1.62 Ibs is equivalent to 734.82 grams

Density of the solid object = 734.82 grams ÷ 190 mL

Density = 3.87g/mL

Therefore, the density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.

Learn more density at: brainly.com/question/20337365

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A 125 mL bubble of hot gases at 213 ∘C and 1.77 atm is emitted from an active volcano. Part A What is the final temperature, in
Svetach [21]

Answer:

T₂  = 242 K

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 125 mL

Initial pressure = 1.77 atm

Initial temperature = 213 °C (213 +273 = 486 K)

Final volume = 136 mL

Final pressure = 0.810 atm

Final temperature = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂T₁ / P₁V₁

T₂ = 0.810 atm × 136 mL × 486 K / 1.77 atm× 125 mL

T₂  =  53537.76 atm .mL.  K  / 221.25 atm . mL

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6 0
3 years ago
2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)
Paha777 [63]
<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                               \displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})
  2. Multiply/Divide:                 \displaystyle 16.6685 \ g \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

16.6685 g H₂O ≈ 16.7 g H₂O

6 0
3 years ago
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