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4 years ago

Which of these molecules are polar? check all that apply. co2 so2 ch2cl2 pcl3?

2 answers:

4 0

Polar molecules are molecules with net dipole due to the presence of partial positive and partial negative charge. For example, water is a polar molecule that has partial positive and partial negative charge on it. CO2 is a non polar compound.

Answer: The following molecules are polar:
SO2- It is polar because it has dipole moment.
CH2Cl2
PCl3

Arlecino [84]4 years ago

4 0

SO2 and PCL3 are all polar. SO2 is polar because it is a non-linear molecule and is slightly more charged on each side. PCL3 is polar because because the dipoles don't completely cancel each other out.

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A. Match each type of titration to its pH at the equivalence point.

maks197457 [2]

Answer:answers are in the explanation

Explanation:

(a). pH less than 7 between 1 - 3.5 are strong acid, and between 4.5-6.9 weak acid.

pH greater than 7; between 10-14 is a strong base, and between 7.1 - 9, it is weakly basic.

(b). Equation of reaction;

HBr + KOH ---------> KBr + H2O

One mole of HBr reacts with one mole of KOH to give one Mole of KBr and one mole of H2O

Calculating the mmol, we have;

mmol KOH = 28.0 ml × 0.50 M

mmol KOH= 14 mmol

mmol of HBr= 56 ml × 0.25M

mmol of HBr= 14 mmol

Both HBr and KOH are used up in the reaction, which leaves only the product,KBr and H2O.

The pH here is greater than 7

(C). [NH4^+] = 0.20 mol L^-1 × 50 ml. L^-1 ÷ 50 mL + 50mL

= 0.10 M

Ka=Kw/kb

10^-14/ 1.8× 10^-5

Ka= 5.56 ×10^-10

Therefore, ka= x^2 / 0.20

5.56e-10 = x^2/0.20

x= (0.20 × 5.56e-10)^2

x= 1.05 × 10^-5

pH = -log [H+]

pH= - log[1.05 × 10^-5]

pH = 4.98

Acidic(less than 7)

(c). 0.5 × 20/40

= 0.25 M

Ka= Kw/kb

kb= 10^-14/1.8× 10^-5

Kb = 5.56×10^-10

x= (5.56×10^-10 × 0.5)^2

x= 1.667×10^-5 M

pH will be basic

3 0

3 years ago

A mixture of CrBr3 and inert material is analyzed to determine the Cr content. First the mixture is dissolved in water. Then all

Masteriza [31]

Answer:

Mass% Cr = 85.5%

Explanation:

Given:

Mass of CrBr3 sample = 0.8409 g

Mass of the AgBr precipitate = 1.0638 g

To determine:

The mass percent of Cr in the sample

Calculation:

The reaction of CrBr3 with silver nitrate results in the precipitation of the bromide ion as silver chloride (AgBr) and Cr as soluble Cr(NO3)2

CrBr3(aq) + 3AgNO3(aq)→ 3AgBr(s) + Cr(NO3)3(aq)

Molecular weight of AgBr =187.77 g/mol

Moles of AgBr precipitated is:

$Moles(AgBr)=\frac{Mass(AgBr)}{Mol.wt(AgBr)}=\frac{0.8409g}{187.77g/mol}=0.004478moles$

Since 1 mole of AgBr contains 1 mole of Cl, therefore:

# moles of Cl = 0.004478 moles

At wt of Cl = 35.45 g/mol

$Mass(Chloride)=moles*at.wt = .004478moles*34.45g/mol=0.1543$

$Mass%(chloride)=\frac{mass(chloride)}{mass(sample)}*100=\frac{0.1543}{1.0638}*100 = 14.50%$

Mass%(Cr) = 100 - 14.50=85.5%

5 0

3 years ago

CO2, NaCI, and HCI may all be classified as...

NARA [144]

the answer would be b. compounds.

4 0

3 years ago

Read 2 more answers

What is the mass in grams of 2.5 mol of O2?

d1i1m1o1n [39]

Answer:

80grams

Explanation:

RAM of O=16

molar mass of O2= 16×2=32g/mol

mass= mole × molar mass

= 2.5×32= 80g

4 0

3 years ago

The burning of propane gas can be represented as a balanced chemical reaction as follows: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calcula

Snezhnost [94]

Answer: 20L of H2O

Explanation:

C3H8 + 5O2 → 3CO2 + 4H2O

Recall 1mole of a gas contains 22.4L at stp

5moles of O2 contains = 5 x 22.4 = 112L

4moles of H2O contains = 4 x 22.4 = 89.6L

From the equation,

112L of O2 produced 89.6L H2O

There for 25L of O2 will produce XL of H2O i.e

XL of H2O = (25 x 89.6)/112 = 20L

6 0

3 years ago