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shutvik [7]
3 years ago
15

On a mission to a newly discovered planet, an astronaut finds gallium abundances of 61.29 % for 69Ga and 39.71 % for 71Ga. What

is the atomic mass of gallium for this location? The mass of 69Ga is 68.7200 amu . The mass of 71Ga is 70.9200 amu .
Chemistry
1 answer:
snow_lady [41]3 years ago
8 0
I believe it is 70.281amu
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How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
What is the correct symbol of an ion containing 17 protons,20 neutrons and 18 electrons
Nataliya [291]

Answer:

The symbol of the ion is A^-

Explanation:

Let A be the symbol of the element.

Proton = 17

Electron = 18

Neutron = 20

Since the element has more electrons than protons, it means it has gain electrons.

From the question given,

The difference between the electron and proton = 18 — 17 = 1

So, the element has gain 1 electron.

Therefore the symbol of the ion is A^-

3 0
3 years ago
How many atoms are in a 1.8 mol sample of Magnesium (Mg)?
Gnom [1K]

Answer:

1.1 × 10²⁴ atoms Mg

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 1.8 mol Mg

[Solve] atoms Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg

5 0
3 years ago
Read 2 more answers
Problem Page A gas made up of atoms escapes through a pinhole 0.225 times as fast as H2 gas. Write the chemical formula of the g
Tcecarenko [31]
To determine what gas is this, we use Graham's Law of Effusion where it relates the rates of effusion of gases and their molar masses. We do as follows:

r1/r2 = √(M2 / M1)

Let 1 be the the unkown gas and 2 the H2 gas.

r1/r2 = 0.225
M2 = 2.02 g/mol

0.225 = √(2.02 / M1)
M1 = 39.90 g/mol

From the periodic table of elements, most likely, the gas is argon.
5 0
3 years ago
Read 2 more answers
A soccer player practices kicking the ball into the goal from halfway down the field the time it takes for the ball to get to th
Nataliya [291]
Velocity = 15 m/s

90/2 = 45 m
45/3 (seconds to reach) = 15 m 



5 0
3 years ago
Read 2 more answers
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