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3 years ago

Solve for x. 10x – 79 = 2x + 49 x = [?]

Mathematics

2 answers:

Harrizon [31]3 years ago

7 0

Answer:

$x = 16$

Step-by-step explanation:

Step 1: Add 79 to both sides

$10x - 79 + 79 = 2x + 49 + 79$

$10x = 2x + 128$

Step 2: Subtract 2x from both sides

$10x - 2x = 2x - 2x + 128$

$8x = 128$

Step 3: Divide 8 from both sides

$\frac{8x}{8} = \frac{128}{8}$

$x = 16$

Answer: $x = 16$

8090 [49]3 years ago

7 0

*jjjjjjjjjjjjjjjjbbbjnjbbbbbbbbhfuh

Step-by-step explanation:

x=16

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a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

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Given Information:

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Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

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