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Bumek [7]
3 years ago
5

Factor completely 9x^2-4

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

(3x-2)(3x+2)

When multiplied out it equals the original expression


jok3333 [9.3K]3 years ago
6 0

I think you means

9x² - 4 which is a difference of squares


difference of squares

a² - b²  can be factored as (a + b)(a - b)

so

9x² - 4

(3x + 2)(3x - 2)


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Answer:

2x^2 = 6x - 5.

-x^2 - 10x = 34.

These have only complex roots/

Step-by-step explanation:

3x^2 - 5x = -8

3x^2 - 5x + 8 = 0

There are complex roots if the discriminant  9b^2 - 4ac) is negative.

Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160

This is positive so the roots are real.

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12x = 9x^2 + 4

9x^2 - 12x + 4 = 0

D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.

- Real roots.

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x^2 + 10x + 34 = 0

D = (10)^2 - 4*1*34 = 100 - 136 = -36.

No real roots = only complex roots.

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1. \frac{x}{15}  = 3

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