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likoan [24]
3 years ago
12

Which of these statements is not true about chemical reaction rates? a Temperature can change a reaction rate. b The amount of r

eactants can increase the reaction rate. c Temperature can decrease the reaction rate. d Temperature does not affect the reaction rate.
Chemistry
1 answer:
Umnica [9.8K]3 years ago
4 0

Answer:

The statement that is not true is: 'Temperature does not affect the reaction rate'.  

Explanation:

a) Temperature can change a reaction rate. <u> This is true</u>

Increasing the temperature increases the reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

For example, the time taken to melt a metal will be much higher at a lower temperature but it will decrease as soon as we increase the temperature

b) The amount of reactants can increase the reaction rate.<u> This is true</u>

A higher concentration of reactants leads to more effective collisions per unit time, which leads to an increased reaction rate.

c) Temperature can decrease the reaction rate. <u>This is true </u>

Decreasing the temperature decreases the reaction rates because of the  decrease in the number of high energy collisions. It will result in a slower reaction.

d) Temperature does not affect the reaction rate.  <u>This is not true. </u>

The reaction rate is temperature dependent. The reaction rate increases with higher temperature and decreases with lower temperature.

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Which statement is true for every compound? THIS QUESTION IS WORTH 39 POINTS H.E.L.P
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3 0
3 years ago
What volume does 1.70 ×10–3 mol of chlorine gas occupy if its temperature is 20.2 °C and its pressure is 795 mm Hg?
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Explanation:

The given data is as follows.

     No. of moles = 1.70 \times 10^{-3},           V = ?

     T = 20.2 + 273 K = 293.2 K,             P = \frac{795 mm Hg}{760.0 mm Hg/atm} = 1.046 atm,                      R = 0.0821 L atm K^{-1}mol ^{-1}

Calculate the volume using ideal gas equation as follows.

                                    P V = n R T

    1.046 atm \times V = 1.70 \times 10^{-3} \times 0.0821 L atm K^{-1}mol ^{-1} \times 293.2 K

                                  V = \frac{1.70 \times 10^{-3} \times 0.0821 L atm K^{-1}mol ^{-1} \times 293.2 K}{1.046 atm}

                                   = \frac{40.921 L atm}{1.046 atm}

                                   = 39.122 \times 10^{-3} L

Thus, we can conclude that volume of the gas is 39.122 \times 10^{-3} L.


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