<h2><em>1. A</em></h2><h2><em>3. B</em></h2><h2><em>4. C</em></h2><h2><em>7. E</em></h2><h2><em>5. F</em></h2>
Answer:
High temperatures
Explanation:
NaHCO₃ (8) + HCH,O₂ (aq) → H₂O (l) + CO₂ (g) + NaC,H₃O₂ (aq)
As the flask gets cooler to the touch as the reaction proceeds, the reaction is endothermic. This means that ΔH is positive (ΔH>0).
As a gas is formed (bubbles are formed), ΔS is positive (ΔS>0).
<em>In terms of ΔG:</em>
<em>In order for the reaction to be thermodynamically favorable, ΔH has to be negative</em>, thus:
- The reaction is favorable if TΔS > ΔH.
The greater the temperature, the easier it would be for TΔS to be greater than ΔH.
Answer:
14.125
Explanation:
If my calculations are right.
- there are 44.0 moles in co2
- +20.0
- which equals 64
- there are 78.125 moles in O2 so just subtract it by 64 which gives you
- 14.125
MOLE CALCULATION
divide the mass of the material by its molar mass. The molar mass of a substance is the mass in grams of one mole of that substance.
I’m not sure if this will help, but protons make different elements. That’s how we can tell the difference between elements!
You would expect to find more water because the acid would parially dissolve
