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4 years ago

5

For their summer holiday, Jane and her family are visiting places surrounding the Mediterranean Sea. Which type of biome is Jane

and her family visiting?

1 answer:

elena-14-01-66 [18.8K]4 years ago

8 0

Temperate grassland . .

You might be interested in

1.00 mole of an ideal gas at STP is cooled to -41°C while the

qwelly [4]

Answer:

V₂ = 18.13 L

Explanation:

Given data:

Mole of gas = 1 mol

Initial temperature = 273 K

Initial pressure = 1 atm

Final volume = ?

Final temperature = -41°C (-41+273 = 232 K)

Final pressure = 805 mmHg (805/760 = 1.05 atm)

Solution:

First of all we will calculate the initial volume of gas.

PV = nRT

V = nRT/P

V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm

V = 22.4 L/atm / 1 atm

V = 22.4 L ( initial volume)

Now we will determine the final volume by using equation,

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values.

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 1 atm × 22.4 L × 232 K / 273 K × 1.05 atm

V₂ = 5196.8 atm .L. K / 286.65 atm.K

V₂ = 18.13 L

5 0

3 years ago

A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.

solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

$Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J$

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

$E = \frac{h \times c }{\lambda }$

where,

h: Planck's constant

c: speed of light

$E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J$

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

$\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J$

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

$Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%$

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0

3 years ago

17. True or False: Proximal means farther away from the point of attachment of the limb. *

olga2289 [7]

True ..... pretty sure

8 0

3 years ago

New industrial plants for acetic acid react liquid methanol (Mm=32g/m) with carbon monoxide in the presen of a catalyst. In an e

Daniel [21]

Answer:

21.42 g

Explanation:

To know this, you need to put the equation that is taking and it's the following:

CH3OH (Methanol) + CO ---------> CH3COOH (Acetic acid)

We already know the mm of methanol, and the mm for CO is:

AM of C = 12 g/mol

AM of O = 16 g/mol

AM of H = 1 g/mol

MM of CO = 12 + 16 = 28 g/m

For acetic acid: 12 + 3(1) + 12 + 16*2 + 1 = 60 g/mol

Now that we know the molar mass of each molecule, let's calculate the number of moles of methanol and CO, because it's easier to work with moles than the grams

moles of methanol = 15/32 = 0.469 moles

moles of CO = 10/28 = 0.357 moles

According to the equation 1 mole of methanol reacts completely with 1 mole of CO. However, in this case, we can see that methanol exceed the CO, so, the CO is the limitant reactant so:

moles reactants of methanol: 0.469 - 0.357 = 0.112 moles.

moles of acid produced: 0.357 moles

This is because we have a ratio of 1:1 between methanol and CO. As methanol exceed CO, the CO is consumed completely leaving a remanant of methanol behind. the whole moles of CO are used, and appears as product of acetic acid, therefore, the moles of acetic acid are the same of CO.

Now with the molar mass of acid, let's calculate the gram of acid, and yield:

g = 0.357 * 60 = 21.42 g of acetic acid.

This is the theorical yield of acetic acid.

5 0

4 years ago

How to comprehend chemistry? A lot of it goes over my head and I don’t know where to start. Advice would be appreciated!

just olya [345]

I recommend this channel called "Crash Course" on youtube and he has a playlist full of chemistry videos he makes it very fun & very easy to understand. Another option i recommend is researching chemistry on this website called "Khan academy" i did and it helped me alott!!

7 0

3 years ago