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Natasha2012 [34]
2 years ago
14

One main difference between a Prokaryotic cell and an Eukaryotic cells is __________.

Chemistry
2 answers:
sasho [114]2 years ago
8 0
The Eukaryotic cell has a nucleus
stepladder [879]2 years ago
4 0

Resposta: 2 - multicelular

4 - A Célula Eucariótica tem um núcleo

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The answer is volume, in gasses, volume depends on the matter, but in solids, volume can be measured.
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The soldiers are issued (infrared) goggles to help them see in the dark.
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Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following
bearhunter [10]

Answer:

210.7~g~MgCO_3

Explanation:

We have to start with the <u>reaction</u>:

MgCO_3~->~MgO~+~CO_2

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:

(12*1)+(16*2)=44~g/mol

In other words: 1~mol~CO_2=~44~g~CO_2. With this in mind, we can calculate the moles:

110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2

Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:

2.5~mol~CO_2=2.5~mol~MgCO_3

With the molar mass of MgCO_3 ((23.3*1)+(12*1)+(16*3)=84.3~g/mol. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:

2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3

I hope it helps!

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3 years ago
Which statement accurately compares the trends in atomic number and atomic mass in the periodic table
Tresset [83]

Answer: is C

Explanation:

Both the atomic mass and the atomic number increase from left to right

6 0
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I don't know which the correct answer it is ???
Virty [35]
When I answered i got D
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3 years ago
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