Eyepiece, finder-scope, optical tube, aperture, focuser, and mount
Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)
v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol
n(Na₂S)=n{Cd(NO₃)₂}=cv
m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv
m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
The answer is acid rain
for study island your welcome :)
PH=-log[H⁺]
pH=-log(1.87×10⁻¹³)
pH=12.72
I hope this helps. Let me know if anything is unclear.
Answer:
Fe(s) → Fe²⁺(aq) + 2e⁻ OXIDATION
Mg²⁺(aq) + 2e⁻ → Mg(s) REDUCTION
Explanation:
The redox reaction is: MgCl₂(aq) + Fe(s) → FeCl₂(aq) + Mg(s)
We need to know that elements in ground state have 0 as the oxidation state.
Iron in the reactants, and Mg in the products
In the magnessium chloride, the Mg acts with+2, so the oxidation state has decreased → REDUCTION
In the iron(II) chloride, the Fe acts with +2, so the oxidation statehas increased → OXIDATION
The half reactions are:
Fe(s) → Fe²⁺(aq) + 2e⁻ OXIDATION
Mg²⁺(aq) + 2e⁻ → Mg(s) REDUCTION
