Answer:
electricity
Explanation:
i took the test and got the answer right.
We can confirm that in a roller coaster, kinetic and potential energy in the car decreases at each successive hill because of the force of gravity which converts potential energy into kinetic energy.
<h3>What are potential and kinetic energy?</h3>
- Potential energy is referred to as <em><u>positional energy</u></em>.
- This means that the object in question gains energy based on its position relative to others.
- Kinetic energy is the energy of movement.
- Gravity causes the roller coaster to fall, losing potential energy.
- This causes it to gain all of the potential energy as kinetic energy.
- Once at the bottom, the coaster no longer moves and thus loses the kinetic energy as well.
Therefore, we can confirm that gravity is the force that causes the shift from potential energy to kinetic energy and thus causes them both to decrease after each successful hill in the roller coaster.
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Answer:
That the isotope H-1 is the most abundant in nature.
Explanation:
Hello!
In this case, since the average atomic mass of an element is computed considering the mass of each isotope and the percent abundance each, for hydrogen we would set up something like this:
Moreover, since the isotope notation H-1 and H-2 means that the atomic mass of H-1 is 1 amu, that of H-2 is 2 amu and the average one is 1.0079 amu, we can infer that the most of the hydrogen in nature is H-1 as the most of it composes the average hydrogen atom.
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The combustion of an organic compound is mostly written as,
CaHbOc + O2 --> CO2 + H2O
where a, b, and c are supposed to be the subscripts of the elements C, H, and O in the compound. Determining the number of moles of C and H in the product which is the same as that in the compound,
(Carbon, C) : (561 mg) x (12/44) = 153 mg x (1 mmole/12 mg) = 12.75
(Hydrogen, H) : (306 mg) x (2/18) = 34 mg x (1 mmole/1 mg) = 34
Calculating for amount of O in the sample,
(oxygen, O) = 255 - 153 mg - 34 mg = 68 mg x (1mmole/16 mg) = 4.25
The empirical formula is therefore,
C(51/4)H34O17/4
C3H8O1
The molar mass of the empirical formula is 60. Therefore, the molecular formula of the compound is,
C9H24O3
