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lutik1710 [3]
2 years ago
10

What element is being oxidized in the following redox reaction?

Chemistry
1 answer:
bogdanovich [222]2 years ago
8 0

Answer:

Cr

Explanation:

Cr goes from +3 to +6 and when it increases it means is being oxidized.

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The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:
LiRa [457]

Explanation:

(a)  As the given chemical reaction equation is as follows.

           OCl^{-} + I^{-} \rightarrow OI^{-1} + Cl^{-1}

So, when we double the amount of hypochlorite or iodine then the rate of the reaction will also get double. And, this reaction is "first order" with respect to hypochlorite and iodine.

Hence, equation for rate law of reaction will be as follows.

              Rate = K \times [OCl^{-}] \times [l^{-}]

(b)  Since, the rate equation is as follows.

                    Rate = K [OCl^{-}][l^{-}]

Let us assume that ([OCl^{-}] = [l^{-}])

Putting the given values into the above equation as follows.

             1.36 \times 10^{-4} = K \times (1.5 \times 10^{-3})^2

            1.36 \times 10^{-4} = K \times (2.25 \times 10^{-6})

                   K = \frac{1.36 \times 10^{-4}}{2.25 \times 10^{-6}}

                      = 60.4 M^{-1}sec^{-1}

Hence, the value of rate constant for the given reaction is 60.4 M^{-1}sec^{-1} .

(c) Now, we will calculate the rate as follows.

                Rate = K [OCl^{-}][l^{-}]

                         = 60.4 \times (1.8 \times 10^{3}) \times (6.0 \times 10^{4})

                        = 6.52 \times 10^{5}

Therefore, rate when [OCl^{-}] = 1.8 \times 10^{3} M and [I^{-}]= 6.0 \times 10^{4} M is  6.52 \times 10^{5}.

8 0
3 years ago
If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?
mamaluj [8]

Answer:

The suitable equation for this reaction is

2CO + O₂ -----> 2CO₂

Here, we are given that we have 2 grams of O₂

From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂

Moles of O₂:

2/32 = 1/16 moles

Therefore, the number of moles of CO₂ is twice the moles of O₂

Moles of CO₂ = 2 * 1/16

Moles of CO₂  formed = 1/8 moles

Mass of CO₂  formed = Molar mass of CO₂ * Moles of CO₂

Mass of CO₂  formed = 44 * 1/8

Mass of CO₂  formed = 5.5 grams

Hence, option B is correct

Kindly Mark Brainliest, Thanks!!!

8 0
3 years ago
Which of the following will occur soon after a population of prey increases slightly in size?
Lady bird [3.3K]
Your answer is D predator population will increase greatly. That's because if there's more prey there will be more food and its good for the predators to produce more because they don't got to worry about food. Speaking how they preys population grew.

So your answer is D.
4 0
3 years ago
TILEF
torisob [31]

Answer:

Na

Explanation:

sodium has mass number 23 and atomic number 11 so number of protons =number of electrons =atomic number which is 11 and number of neutrons=mass number-number of protons =23-11=12

7 0
3 years ago
Order the following elements based upon their electronegativity, highest to lowest: carbon, flourine, hydrogen, nitrogen, oxygen
SOVA2 [1]

Answer:

The correct order is: Fluorine; Oxygen; Nitrogen; Carbon; Hydrogen; Sodium.

Explanation:

The electronegativity in the periodic table increases to the right in a period and up in a group. We can figure out the electronegativity of each element according to its electron configuration:

Carbon: [He] 2s^{2} 2p^{2}

Fluorine: [He] 2s^{2} 2p^{5}

Hydrogen: 1s^{1}

Nitrogen: [He] 2s^{2} 2p^{3}

Oxygen: [He] 2s^{2} 2p^{4}

Sodium: [Ne] 3s^{1}

The period of a chemical element is given by the last energy level of electron configuration.

The group of a chemical element is given by the amount of electrons in the last energy level of electron configuration.

Therefore,

Carbon: Period 2 Group 4

Fluorine: Period 2 Group 7

Hydrogen: Period 1 Group 1

Nitrogen: Period 2 Group 5

Oxygen: Period 2 Group 6

Sodium: Period 3 Group 1

Electronegativity increases when the number of the group increases.

Electronegativity increases when the number of the period decreases.

In conclusion, Fluorine has the greatest number of group and Sodium has the lowest number of group (also it has a greater number of period than hydrogen, so it is less electronegative than hydrogen)

F>O>N>C>H>Na

8 0
3 years ago
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