A chemist prepares a solution of sodium chloride(NaCl) by measuring out 25.4g of sodium chloride into a 100ml volumetric flask a
nd filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium chloride solution. Round your answer to significant digits.
2 answers:
Answer: 4 molL-1
Explanation:
Detailed solution is shown in the image attached. The number of moles of NaCl is first obtained. Since the molarity must be in units of molL-1, the volume is divided by 1000 and the formula stated in the solution is applied and the answer is given to one significant figure.
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Answer:
n = 1.075 moles
Explanation:
Given that,
Mass of oxygen = 34.4 gram
The molar mass of oxygen gas = 32 g/mol
We need to find the number of moles of oxygen. We know that,
No. of moles = given mass/molar mass
So,
So, there are 1.075 moles in 34.4 g of Oxygen gas.