<span>Answer:
Molecular:
HC2H3O2(aq) + KOH(aq) --> KC2H3O2(aq) + H2O(l)
Complete ionic:
HC2H3O2(aq) + K+(aq) + OH-(aq) --> K+(aq) + C2H3O2-(aq) + H2O(l)
Net Ionic:
HC2H3O2(aq) + OH-(aq) --> C2H3O2-(aq) + H2O(l)</span>
Answer:86
Explanation: to find atomic mass you take the number of protons and the number of neutrons. therefore you take the 40 protons and the 46 neutrons to find the mass. :)
Answer:
The answer to your question is given below
Explanation:
1. When two hydrogen atoms pair together, they form a single bond to achieve complete duet.
Hydrogen atom has 1 shell and 1 valence electron and they contribute it to form bond, thereby obtaining a stable duet configuration
H + H —> H–H —> H2
2. When two halogen atom pair together, they form a single bond to achieve a complete octet which is stable. For example, Cl has 7 electrons in its outermost shell and need 1 more electron to complete it octet. Each Cl will contribute 1 electron each to form a single bond..
Cl + Cl —> Cl–Cl —>Cl2
3. When two oxygen atoms pair together, they form double bond to achieve a complete octet which is a stable configuration.
Oxygen has 6 electrons in its outermost shell and needs 2 more electrons to complete its octet configuration. Each oxygen atom will contribute 2 electrons each to form a double in order to complete it octet configuration.
O + O —> O=O —>O2
4. When two nitrogen atom pair together, they form a triple bond to achieve a complete octet which is stable. Nitrogen has 5 electrons in its outermost shell and needs 3 more electrons to complete it octet configuration. Each nitrogen atom will contribute 3 electrons each to form a triple bond in order to complete its octet configuration.
N + N —> N≡N —> N2.
Honey<span> is a </span>homogeneous<span> mixture because it has the properties that define</span>homogeneous<span> solutions or mixtures.</span>
Answer:
• 2,1,2
Explanation:
aMg +b O2 --> cMgO
Rule of balancing :-<em><u> </u></em><em><u>Num</u></em><em><u>ber</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>atom</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>element </u></em><em><u>should</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>both</u></em><em><u> </u></em><em><u>side</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>equation</u></em><em><u>.</u></em>
Balancing O :- 2b = c
( now by hit and trial method )
for b = 1 => c = 2
and Balancing Mg :-
c= 2 and c = a
=> a = 2
<h3>
2Mg + O2 ---> 2MgO</h3>