– liquids, solids or gases – are made up of atoms and molecules that are in constant motion.<span> The theory also states that collisions between atoms and molecules are elastic</span>
To solve this problem, we must assume ideal gas behaviour so
that we can use Graham’s law:
vA / vB = sqrt (MW_B / MW_A)
where,
<span>vA = speed of diffusion of A (HBR)</span>
vB = speed of diffusion of B (unknown)
MW_B = molecular weight of B (unkown)
MW_A = molar weight of HBr = 80.91 amu
We know from the given that:
vA / vB = 1 / 1.49
So,
1/1.49 = sqrt (MW_B / 80.91)
MW_B = 36.44 g/mol
Since this unknown is also hydrogen halide, therefore this
must be in the form of HX.
HX = 36.44 g/mol , therefore:
x = 35.44 g/mol
From the Periodic Table, Chlorine (Cl) has a molar mass of
35.44 g/mol. Therefore the hydrogen halide is:
HCl
Asexual reproduction involves the production of offspring without the need for a secondary partner to contribute genetic information.
Pollination and mating are two forms of sexual reproduction, so B, C, and D are incorrect. A, because the new potato grows directly from the old without the contribution of new genetic material, asexually reproduces.
Answer:
10.49
Explanation:
3MgO + 2Fe — Fe2O3 + 3Mg
n(Fe2O3) = m/M
=15/159.69
=0.9393199324mol
1 Mol of Fe2O3 = 2 moles of Fe
Therefore n(Fe) =2 * 0.9393199324
=0.1878639865mol
m(Fe) = n*m.m
= 0.1878639865 * 55.8
=10.4828g
The correct answer is option 4 and 5.
The electron domain geometry for an ammonia molecule, NH₃ has tetrahedral electron domain geometry. In NH₃ there are three bond pair electrons and one lone pair electron. Therefore, NH₃ has four electron pairs which are distributed in a tetrahedral shape.
The molecular geometry for an ammonia molecule, NH₃ is trigonal-pyramidal molecular geometry. Ammonia has one lone pair of electron and three bond pairs of electrons thus the resulting molecular geometry is trigonal-pyramidal.
