$cis(x)=\cos x+i\sin x\\\\cis15^o=\cos15^o+i\sin15^o\\\\\cos15^o=\dfrac{\sqrt6+\sqrt2}{4};\ \sin15^o=\dfrac{\sqrt6-\sqrt2}{4}\\\\\text{therefore}\\\\7cis15^o=7\left(\cos15^o+i\sin15^o\right)=7\cos15^o+7i\sin15^o\\\\=7\left(\dfrac{\sqrt6+\sqrt2}{4}\right)+7\left(\dfrac{\sqrt6-\sqrt2}{4}\right)i$

6 0

2 years ago

A tub is filled with 18000 cm3 of water. It loses one-tenth of its water every 12 hours. What volume of water would be remaining

Lina20 [59]

Answer:

0 cm³

Step-by-step explanation:

the lost of water =

(5×24)/12 x 1/10 × 18000

= 10/10 × 18000 = 18,000 cm³

so, the remaining water in the tub=

18,000 - 18,000 = 0 cm³

(the tub is empty)

6 0

2 years ago

Can anyone help me to solve this please??

andre [41]

Answer:

Step-by-step explanation: explique melhor

7 0

2 years ago

40 pints of juice in 2 containers

mezya [45]

Answer:

Step-by-step explanation:

5 0

3 years ago