What is the maximum mass of sugar that could be dissolved in 1.3 l of water?

1 answer:

6 0

Answer is: <span>the maximum mass of sugar that could be dissolved in 1.3 l of water in room temperature is 2652 grams.
</span><span>The solubility of sugar in water in room temperature is 204 g/100 ml.
Make proportion, if 204 grams of sugar dissolve in 100 ml of water, than how much dissolve in 1300 ml of water:
204 g : 100 ml = m(sugar) : 1300 ml.
m(sugar) = 204 g </span>· 1300 ml ÷ 100 ml.
m(sugar) = 2652 g ÷ 1000 g/kg = 2,652 kg.

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Determine the oxidation state of nitrogen in lino3.

Andre45 [30]

Answer : The oxidation state of nitrogen in $LiNO_3$ is, (+5)

Explanation :

Rules for the oxidation numbers :

The oxidation number of a free element is always be zero.
The oxidation number of a monatomic ion equal to the charge of the ion.
The oxidation number of Hydrogen (H) is +1.
The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in the peroxides.
The oxidation number of a Group 1 element in a compound is +1.
The oxidation number of a Group 2 element in a compound is +2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is, $LiNO_3$

Let the oxidation state of 'N' be, 'x'

$(+1)+x+3(-2)=0\\\\x=+5$