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kenny6666 [7]
3 years ago
6

In a gas the kinetic energy is?

Chemistry
1 answer:
Mice21 [21]3 years ago
8 0

Answer:

The kinetic energy of the translational motion of an ideal gas depends on its temperature.

Explanation:

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Why an offspring and its parent share many common traits?
blondinia [14]

Answer:

Explanation: Traits are characteristics, such as its size or height and that comes from parents or other relatives.

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2 years ago
Which of the following are polyatomic ions? Check all that apply
stellarik [79]

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NH4 is the correct ans

Explanation:

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3 years ago
In the lab vinegar acetic acid was mixed with baking soda sodium bicarbonate to form dioxide gas and sodium acetate. What are th
SpyIntel [72]

2CH3COOH +Na2CO3 ----> 2CH3COONa + H20 + CO2

know you can find what all products formed from his reaction

4 0
3 years ago
What is the conjugate acid in the following equation:
yanalaym [24]

Answer:

HNO₂

Explanation:

An acid is a proton donor; a base is a proton acceptor.

Thus, NO₂⁻ is the base, because it accepts a proton from the water.

H₂O is the acid, because it donates a proton to the nitrite ion.

The conjugate base is what's left after the acid has given up its proton.

The conjugate acid is what's formed when the base has accepted a proton.

NO₂⁻/HNO₂ make one conjugate acid/base pair, and H₂O/OH⁻ are the other conjugate acid/base pair.

NO₂⁻ + H₂O ⇌ HNO₂ + OH⁻

base     acid     conj.      conj.

                        acid       base

5 0
3 years ago
2.50 liter of a gas has a pressure of 165. kPa at 25.0°C. If the pressure increases to 600. kPa and the temperature to 100.0°C,
tiny-mole [99]

Answer:

0.861 L

Explanation:

We are given pressure, volume, and temperature, so let's apply the Combined Gas Law:

(P₁V₁)/T₁ = (P₂V₂)/T₂

Convert the temperatures to degrees Kelvin.

25.0°C -> 298 K, 100.0°C -> 373 K

Plug in the initial conditions on the left, then the final/new on the right, and solve for the unknown:

(165(2.5))/298 = (600(V₂))/373

V₂ = (165(2.5)(373))/(298(600))

V₂ = 0.861 L

7 0
3 years ago
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