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lana [24]
3 years ago
6

The half-life of carbon-14 is 5370 years. The carbon-14 levels in a fossil indicate that 6 half-lives have passed. How old is th

e fossil?
32,220 years
75,200 years
50,000 years
35,000 years
Physics
2 answers:
vodomira [7]3 years ago
8 0
On half life is 5370 years; 6 half lives have passed. You just multiply,

5370*6 = 32,220 years
Stella [2.4K]3 years ago
8 0

Answer: 35,000 years

Explanation: Radioactive process follow first order kinetics.

To calculate the rate constant, we use the formula:

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5370years}}

k=1.2\times 10^{-4} years^{-1}

Also : a=\frac{a_o}{2^n}

where,  

a = amount of reactant left after n-half lives

a_o = Initial amount of the reactant

n = number of half lives = 6

Putting values in above equation, we get:

2^6=\frac{a_0}{a}

64=\frac{a_0}{a}

The rate expression for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a_0}{a}

where,

k = rate constant

t = time taken for decay process

a_0  = initial amount of the reactant

a = amount left after decay process

Putting values in above equation, we get:

t=\frac{2.303}{1.2\times 10^{-4}}\log{64}

t=35000years

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