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solong [7]
3 years ago
11

Are stairs a type of inclined plane?

Physics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

imma say yes

Explanation:

-BARSIC- [3]3 years ago
3 0

Answer:

Inclined planes are simple machines used to make work easier. Ramps, ladders, and staircases are all inclined planes.

Explanation:

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Draw velocity-ime graph for uniform moion of an object , when initially body is at rest.
Klio2033 [76]
When the body is at rest, its speed is zero, and the graph lies on the x-axis.

When the body is in uniform motion, the speed is constant, and the graph is a horizontal line, parallel to the x-axis and some distance above it.

It's impossible to tell, based on the given information, how these two parts of the
graph are connected.  There must be some sloping (accelerated) portion of the graph
that joins the two sections, but it cannot be accounted for in either the statement
that the body is at rest or that it is in uniform motion, since acceleration ... that is,
any change of speed or direction ... is not 'uniform' motion'.
8 0
3 years ago
A 750-newton person stands in an elevator that is
blondinia [14]
When an elevator is accelerating downward, the normal force is equal to mg-ma (hence you feel a little lighter when accelerating downwards)

Therefore, the upward force of the elevator floor on the person must be less than 750N
8 0
3 years ago
What will occur if a resistor with high resistance is inserted into a circuit?
Anton [14]
If the resistor is in series with the rest of the circuit then a is the correct answer. The voltage across the resistor in series with another resistor is
V \frac{R}{R+r}
where R is the big resistor and r is the small one and V is the total voltage drop across both.  This is called a voltage divider
5 0
3 years ago
Read 2 more answers
A sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density? <br>​
Hoochie [10]

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]

And the mass m = 4 [gramm] = 0.004 [kg]

Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]

3 0
3 years ago
Suppose a spring has a relaxed length of 28.3 cm. The simulation refers to this as the natural length. This is the length of the
den301095 [7]

Answer:

Explanation:

Normal length of spring = 28.3 cm

stretched length of spring = 38.2 cm

length of extension = 38.2 - 28.3 = 9.9 cm

= 9.9 x 10⁻² m

force applied to stretch = .55 x 9.8 ( mg )

= 5.39 N

Force constant = force applied / extension

= 5.39 / 9.9 x 10⁻²

= .5444 x 10² N /m

= 54.44 N/m

4 0
3 years ago
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